Sequential Circuits MCQ Quiz - Objective Question with Answer for Sequential Circuits - Download Free PDF
Last updated on Jun 23, 2025
Latest Sequential Circuits MCQ Objective Questions
Sequential Circuits Question 1:
The J input of a JK flipflop is connected to logical 1. The K input is connected to Q'(Q complement) of the same flipflop. Assume that the flipflop is initially cleared and then 6 clock pulses are applied. What is the output sequence at Q?
Answer (Detailed Solution Below)
Sequential Circuits Question 1 Detailed Solution
Concept:
A JK flip-flop toggles its output on every clock pulse when both J and K are high.
Given configuration:
- J = 1 (logic high)
- K = Q′ (complement of Q)
This means K will be 1 when Q is 0, and K will be 0 when Q is 1.
Initial Condition:
Q = 0 (flip-flop is initially cleared)
Apply 6 Clock Pulses:
Clock Pulse | Q | K = Q′ | JK Flip-Flop Behavior |
---|---|---|---|
1 | 0 → 1 | 1 | J = 1, K = 1 → Toggle |
2 | 1 → 1 | 0 | J = 1, K = 0 → Set |
3 | 1 → 1 | 0 | J = 1, K = 0 → Set |
4 | 1 → 1 | 0 | J = 1, K = 0 → Set |
5 | 1 → 1 | 0 | J = 1, K = 0 → Set |
6 | 1 → 1 | 0 | J = 1, K = 0 → Set |
Final Output Sequence at Q:
0 1 1 1 1 1
→ 011111
Sequential Circuits Question 2:
Initial conditions of 4 bit serial in parallel out right shift register is 1010 and is connected as shown in figure. What is the content after 3 clock cycles ?
Answer (Detailed Solution Below)
Sequential Circuits Question 2 Detailed Solution
Concept:
A 4-bit Serial-In Parallel-Out (SIPO) Right Shift Register shifts bits to the right on each clock pulse. The MSB is filled from a serial input, which in this case is connected to the LSB output (feedback loop).
Clock Cycle | Register Content (MSB to LSB) | Feedback (LSB) | Action |
---|---|---|---|
Initial | 1 0 1 0 | 0 | Initial condition |
After 1st | 0 1 0 1 | 1 | Shift right, insert 0 at MSB |
After 2nd | 1 0 1 0 | 0 | Shift right, insert 1 at MSB |
After 3rd | 0 1 1 1 | 1 | Shift right, insert 0 at MSB |
Final Answer: 0111 (Option 2)
Sequential Circuits Question 3:
The state transition diagram for the diagram given is
Answer (Detailed Solution Below)
Sequential Circuits Question 3 Detailed Solution
Concept:
The circuit contains a T Flip-Flop (TFF) whose T input is selected via a 2:1 MUX. The selection line of the MUX is S.
We know that the behavior of a T Flip-Flop is as follows:
- If T = 0 → No change in Q (hold state)
- If T = 1 → Toggle the state of Q
The MUX selects between two inputs: i0 and i1. Let’s assume:
- i0 = 0 (for S = 0) → T = 0 → Q holds
- i1 = 1 (for S = 1) → T = 1 → Q toggles
State Behavior:
- When S = 0 → T = 0 → Q holds its current state
- When S = 1 → T = 1 → Q toggles (0 ↔ 1)
Transition Summary:
- If Q = 0 and S = 0 → Q remains 0
- If Q = 0 and S = 1 → Q toggles to 1
- If Q = 1 and S = 0 → Q remains 1
- If Q = 1 and S = 1 → Q toggles to 0
Answer:
Option 4: State transition diagram matches the toggling/hold behavior correctly
Sequential Circuits Question 4:
If A & B are 8 bit right shift registers connected as shown in fig. and the initial values of A & B in hexadecimal are B2 and OF respectively, the value of A in hexadecimal after 6 clock pulses is
Answer (Detailed Solution Below)
Sequential Circuits Question 4 Detailed Solution
Initial Values:
- Register A (Initial Value): B2 (in hexadecimal)
- Register B (Initial Value): OF (in hexadecimal)
Binary Representation of Initial Values:
- B2 (Hexadecimal) = 10110010 (Binary)
- OF (Hexadecimal) = 00001111 (Binary)
Analysis of Right Shift Operation:
Clock Pulse | Register B (8-bit) | Output Bit from B (→ A input) | Register A (Before) | Register A (After Shift) | A (Hex) |
---|---|---|---|---|---|
0 (Initial) | 00001111 (0F) | – | 10110010 (B2) | 10110010 | B2 |
1 | 00000111 | 1 | 10110010 | 11011001 | D9 |
2 | 00000011 | 1 | 11011001 | 11101100 | EC |
3 | 00000001 | 1 | 11101100 | 11110110 | F6 |
4 | 00000000 | 1 | 11110110 | 11111011 | FB |
5 | 00000000 | 0 | 11111011 | 01111101 | 7D |
6 | 00000000 | 0 | 01111101 | 00111110 | 3E |
Sequential Circuits Question 5:
In an asynchronous counter, the clock input of each flip-flop except first flip-flop is connected to:
Answer (Detailed Solution Below)
Sequential Circuits Question 5 Detailed Solution
The correct answer is: 2) the output of the previous flip-flop
Explanation:
In an asynchronous counter (also called a ripple counter):
Only the first flip-flop receives the external clock signal.
Each subsequent flip-flop is triggered by the output (Q or Q̅) of the previous flip-flop, not by a common clock.
This causes a ripple effect, where changes propagate sequentially, leading to a slight delay between stages.
Additional Information
Asynchronous Counter
Asynchronous counters are those counters where the clock of the next stage is obtained from the output of the previous state.
Top Sequential Circuits MCQ Objective Questions
The S-R latch is an example of:
Answer (Detailed Solution Below)
Sequential Circuits Question 6 Detailed Solution
Download Solution PDFExplanation:
Latches and Flip-Flop:
- Latches and flip-flops are the basic elements to store 1-bit of data. Hence they are also known as a one-bit memory element.
- Latches change the output continuously when there is a change in the input, i.e. they are level triggered.
- Flip-flop is a combination of latch and clock. It changes the output that is adjusted by the clock.
- The main difference between a latch and a flip-flop is that a flip-flop has a clock signal, whereas a latch does not.
- We can say that a flip-flop without a clock is a latch.
- Latches are asynchronous, which means that the output of a latch depends on its input.
- Basically, there are 4 types of latches: SR latch, JK latch, D latch, T latch.
How many input terminal is represented by T flip flop?
Answer (Detailed Solution Below)
Sequential Circuits Question 7 Detailed Solution
Download Solution PDFT flip flop
The "T Flip Flop" has only one input.
It has only two output states i.e. hold and toggle.
For T = 0, the output is Qn (Hold state)
For T = 1, the output is
The output equation of the T flip-flop is:
Qn+1 = T ⊗ Qn
T |
Qn+1 |
0 |
No change |
1 |
Toggle |
Number of unused states in a 4 bit-Johnson counter are:
Answer (Detailed Solution Below)
Sequential Circuits Question 8 Detailed Solution
Download Solution PDFConcept:
A Johnson counter is a modified ring counter, where the inverted output from the last flip flop is connected to the input to the first.
The MOD of the Johnson counter is 2n if n flip-flops are used.
The circuit diagram for a 4-bit Johnson Counter is as shown:
Calculation:
Total number of states in 4-bit counter are: 2n = 24 = 16
Total states in Johnson counter are: 2n = 2.(4) = 8
Unused states are 16 - 8 = 8In a J-K flip-flop, if J = K̅, then it acts as a/an:
Answer (Detailed Solution Below)
Sequential Circuits Question 9 Detailed Solution
Download Solution PDFD flip flop:
D flip flop has only one input terminal. The output of the D flip flop will be the same as the input. Hence, it is used in delay circuits.
The circuit is as shown below.
Logic symbol:
Truth table:
D |
Qn (Present state) |
Qn+1 (Next state) |
0 |
0 |
0 |
0 |
1 |
0 |
1 |
0 |
1 |
1 |
1 |
1 |
Characteristic equation: Qn+1 = D
The D flip flop may be obtained from an S-R flip flop by just putting one inverter between the S and R as shown in the figure below.
S = R̅
The D flip flop may be obtained from a J-K flip flop by just putting one inverter between the J and K as shown in the figure below.
K = J̅
T flip flop:
T flip flop has only one input terminal. The output of the T flip flop will be toggled when the input is high on every new clock pulse. The output will be the same as the previous state when the input is low.
The circuit is as shown below.
Logic symbol:
Truth table:
T |
Qn (Present state) |
Qn+1 (Next state) |
0 |
0 |
0 |
0 |
1 |
1 |
1 |
0 |
1 |
1 |
1 |
0 |
Characteristic equation: Qn+1 = TQ̅n + T̅Qn
The T flip flop may be obtained from a J-K flip flop by making both the inputs are the same i.e. J = K.
The number of flip-flops required for constructing a mod-12 counter is :
Answer (Detailed Solution Below)
Sequential Circuits Question 10 Detailed Solution
Download Solution PDFThe correct answer is option 2): 4
Concept:
For a counter with ‘n’ flip flops:
- The total number of states = 2n (0 to 2n – 1)
- The largest number that can be stored in the counter = 2n – 1
- To construct a counter with any MOD number, the minimum number of flip flops required must satisfy: Modulus ≤ 2n
- Where n is the number of flip-flops and is the minimum value satisfying the above condition.
- Note: A MOD-N counter is also called as a divide by N counter as the input frequency is divided by the number of states of the counter.
Calculation:
Number no. of flip – flops are required to construct mod-12 counter,
must satisfy: 2n ≥ 12 The minimum value of n satisfying the above is: n = 4
A basic memory storage element in a digital system is:
Answer (Detailed Solution Below)
Sequential Circuits Question 11 Detailed Solution
Download Solution PDF- Latches and flip-flops are the basic elements for storing information. They are made of logic gates.
- One latch or flip-flop can store a 1-bit of information.
- For latches, its input can affect the output as long as the enable signal is asserted (high).
- For flip-flop, its input can affect the output only when the enable signal changes (falling edge or rising edge).
The difference between latches and flip flops is shown
Latches |
Flip Flops |
Latches are building block of sequential circuits and they are built using logic gates |
Flip flops are also building blocks of sequential circuits but they are made using latches |
Latches continuously change the input and output changes correspondingly |
Flip flop output changes only when the clock is applied |
Latches are level sensitive |
Flip flops are edge sensitive |
Three T flip flops are connected to form a counter. The maximum states possible for the counter will be:
Answer (Detailed Solution Below)
Sequential Circuits Question 12 Detailed Solution
Download Solution PDFConcept:
For a counter with ‘n’ flip flops:
- The total number of states = 2n (0 to 2n – 1)
- The largest number that can be stored in the counter = 2n – 1
To construct a counter with any MOD number, the minimum number flip flops required must satisfy:
Modulus ≤ 2n
Where n is the number of flip-flops and is the minimum value satisfying the above condition.
Calculation:
The total number of states required when n = 3:
23 ≥ 8
The states will vary from (0 to 7)
So the maximum states possible for the counter will be 8.
A __________ counter can be implemented using three flipflops.
Answer (Detailed Solution Below)
Sequential Circuits Question 13 Detailed Solution
Download Solution PDFConcept:
For a counter with ‘n’ flip flops:
- The total number of states = 2n (0 to 2n – 1)
- The largest number that can be stored in the counter = 2n – 1
To construct a counter with any MOD number, the minimum number flip flops required must satisfy:
Modulus ≤ 2n
Where n is the number of flip-flops and is the minimum value satisfying the above condition.
Calculation:
Given:
n = 3
Modulus ≤ 2n
Modulus ≤ 23
Modulus ≤ 8
The most appropriate answer is option 1 i.e. Mod 6.
The number of unused states in a n-bit Johnson Counter is:
Answer (Detailed Solution Below)
Sequential Circuits Question 14 Detailed Solution
Download Solution PDFJohnson Counter:
A Johnson counter is a modified ring counter, where the inverted output from the last flip flop is connected to the input to the first.
The circuit diagram for a 4-bit Johnson Counter is as shown:
The MOD of the Johnson counter is 2n if n flip-flops are used.
For an n-bit counter, the total number of states possible is 2n. ∴ The number of unused states for a Johnson counter will be:
Unused = Total States possible - Mod of the counter
= 2n - 2n
Which of the following is not a sequential circuit?
Answer (Detailed Solution Below)
Sequential Circuits Question 15 Detailed Solution
Download Solution PDFThe correct answer is option 4):(Multiplexer)
Concept:
- Combinational logic is a type of digital logic that is implemented by Boolean circuits, where the output is a pure function of the present input only.
- Sequential logic is a type of digital logic in which the output depends not only on the present input but also on the history of the output.
- Sequential logic has memory while combinational logic does not.
- Flip-flop, counter, and shift registers are sequential circuits whereas multiplexer, decoder, and encoder act like combinational circuits.
- A multiplexer also known as a data selector, is a device that selects between several analog or digital input signals and forwards the selected input to a single output line. The selection is directed by a separate set of digital inputs known as select lines.
- The Multiplexer has shown as
Additional Information
- A flip-flop is a sequential digital electronic circuit having two stable states that can be used to store one bit of binary data. Flip-flops are the fundamental building blocks of all memory devices.
- The counter is a sequential circuit consisting of a set of flip-flops which can go through a sequence of states. It is used to count the number of clock cycles. Since the clock pulses occur at known intervals, the counter can be used for measuring time such as period or frequency.
- A shift register is a type of digital circuit using a cascade of flip-flops where the output of one flip-flop is connected to the input of the next. They share a single clock signal, which causes the data stored in the system to shift from one location to the next.