Semiconductor Diode MCQ Quiz - Objective Question with Answer for Semiconductor Diode - Download Free PDF

Last updated on May 17, 2025

Latest Semiconductor Diode MCQ Objective Questions

Semiconductor Diode Question 1:

Given below are two statements:

Statement I: Photovoltaic devices can convert electricity into optical radiation .

Statement II: Zener diode is designed to operate under forward bias in breakdown region.

In the light of the above statements, choose the most appropriate answer from the options given below:

  1. Both Statement I and Statement II are correct.
  2. Both Statement I and Statement II are incorrect.
  3. Statement I is correct but Statement II is incorrect.
  4. Statement I is incorrect but Statement II is correct.

Answer (Detailed Solution Below)

Option 3 : Statement I is correct but Statement II is incorrect.

Semiconductor Diode Question 1 Detailed Solution

The correct answer is Both Statement I and Statement II are incorrect.

Key Points

  • Photovoltaic devices convert optical radiation into electricity. These devices, such as solar panels, utilize the photovoltaic effect to generate electrical energy from light energy.
  • The photovoltaic effect is a process in which light photons are absorbed by a material, typically a semiconductor, causing the release of electrons and creating an electric current.
  • Zener diodes are designed to operate in the reverse bias condition, specifically in the breakdown region.
  • In the breakdown region, a Zener diode allows current to flow in the reverse direction when the voltage exceeds the breakdown voltage, which is a characteristic feature of Zener diodes.
  • Zener diodes are commonly used for voltage regulation in electronic circuits, ensuring a stable output voltage despite variations in the input voltage or load conditions.

 Additional Information

  • Statement I
    • Photovoltaic devices are crucial in renewable energy systems, particularly in solar power generation, where they convert sunlight directly into electricity.
    • These devices are made of materials such as silicon, which have properties that allow them to absorb photons and release electrons, creating an electric current.
  • Statement II
    • Zener diodes are specifically designed to maintain a constant voltage across their terminals when reverse-biased and the applied voltage reaches the Zener breakdown voltage.
    • This property makes Zener diodes useful in applications requiring precise voltage regulation, such as power supplies and voltage reference circuits.

Semiconductor Diode Question 2:

A zener diode of zener voltage 30 V is connected in a circuit as shown in the figure. The maximum current through the zener diode is

qImage67113cb1a9ca21fd7b3e72a8

  1. 5 mA
  2. 14 mA
  3. 9 mA
  4. 7 mA
  5. 3 mA

Answer (Detailed Solution Below)

Option 1 : 5 mA

Semiconductor Diode Question 2 Detailed Solution

Concept Used:

The Zener diode operates in reverse breakdown mode and maintains a constant voltage across it, irrespective of changes in input voltage or load resistance.

For a maximum current calculation , we consider the highest supply voltage (100V).

The voltage drop across the series resistors (R1 and R2) can be determined as:

VR1+R2 = Vinput - VZener

where:

Vinput = 100V

VZener = 30V

Calculation:

Voltage across 5kΩ + 2kΩ resistors :

VR1+R2 = 100V - 30V = 70V

Total resistance in series:

Rtotal = 5kΩ + 2kΩ = 7kΩ

Total current through the circuit:

Itotal = VR1+R2 / Rtotal

Itotal = 70V / 7kΩ

Itotal = 10 mA

Current through 6kΩ resistor (load current):

Iload = VZener / Rload

Iload = 30V / 6kΩ

Iload = 5 mA

Zener diode current:

IZener = Itotal - Iload

IZener = 10 mA - 5 mA

IZener = 5 mA

∴ The maximum current through the Zener diode is 5 mA.

Semiconductor Diode Question 3:

The concentration of electrons in an intrinsic semiconductor is \(6 \times 10^{15} \text{ m}^{-3}\). On doping with an impurity the electron concentration increases to \(4 \times 10^{22} \text{ m}^{-3}\) In thermal equilibrium, the concentration of the holes in the doped semiconductor is

  1. \(18 \times 10^{-8} \text{ m}^{-3}\)
  2. \(1.5 \times 10^{-7} \text{ m}^{-3}\)
  3. \(9 \times 10^{8} \text{ m}^{-3}\)
  4. \(\frac{2}{3} \times 10^{7} \text{ m}^{-3}\)

Answer (Detailed Solution Below)

Option 3 : \(9 \times 10^{8} \text{ m}^{-3}\)

Semiconductor Diode Question 3 Detailed Solution

Concept:

Intrinsic and Doped Semiconductor:

  • In an intrinsic semiconductor, the electron concentration (nᵢ) is equal to the hole concentration (pᵢ), and they are related by the equation:
    nᵢ = pᵢ = 6 × 10¹⁵ m⁻³ (Given for intrinsic semiconductor)
  • When a semiconductor is doped, the electron concentration increases, and the hole concentration decreases. However, in thermal equilibrium, the product of the electron concentration (n) and the hole concentration (p) remains constant and is given by:
    n × p = nᵢ²
  • After doping, the electron concentration (n) increases to 4 × 10²² m⁻³. The concentration of holes (p) can be found using the above relation, where nᵢ² is the product of the intrinsic carrier concentration.
  • So, in thermal equilibrium, the hole concentration is:
    p = nᵢ² / n

 

Calculation:

Given,

Initial electron concentration in intrinsic semiconductor, nᵢ = 6 × 10¹⁵ m⁻³

After doping, the electron concentration, n = 4 × 10²² m⁻³

The product of electron and hole concentration is given by:

n × p = nᵢ²

p = nᵢ² / n = (6 × 10¹⁵)² / (4 × 10²²)

p = 36 × 10³⁰ / 4 × 10²²

p = 9 × 10⁸ m⁻³

∴ The concentration of holes in the doped semiconductor is 9 × 10⁸ m⁻³.
Hence, the correct option is 3) 9 × 10⁸ m⁻³.

Semiconductor Diode Question 4:

In the diagram shown, the Zener diode has a reverse breakdown voltage of VZ. The current through the load resistance RL is IL.The current through the Zener diode is  

qImage6706415e16972ef286c25439

  1. \(\frac{v_o-v_z}{R_S}\)
  2. \(\frac{v_o-v_z}{R_L}\)
  3. \(\frac{v_z}{R_L}\)
  4. \(\left(\frac{v_o-v_z}{R_S}\right)-I_L\)
  5. \(\left(\frac{v_z-v_o}{R_S}\right)-I_L\)

Answer (Detailed Solution Below)

Option 4 : \(\left(\frac{v_o-v_z}{R_S}\right)-I_L\)

Semiconductor Diode Question 4 Detailed Solution

Given:

A Zener diode is connected in the reverse breakdown region with a series resistor RS and load resistor RL. The input voltage is V0, the Zener voltage is VZ, and the current through the load resistance is IL. We need to calculate the current through the Zener diode, IZ.

Concept:

  • In a Zener diode circuit, the total current through the series resistor RS splits into two parts:
    • Current through the load resistance RL: IL.
    • Current through the Zener diode: IZ.
  • Using Kirchhoff's Voltage Law (KVL) for the input loop:

    V0 - ISRS - VZ = 0.

    Therefore, the total current through the series resistor is:

    IS = (V0 - VZ) / RS.

  • The current through the Zener diode is the difference between the total current IS and the load current IL:

    IZ = IS - IL.

Calculation:

Step-by-step calculation:

1. Total current through the series resistor:

IS = (V0 - VZ) / RS.

2. Current through the Zener diode:

IZ = IS - IL.

Substitute IS:

IZ = (V0 - VZ) / RS - IL.

∴ The current through the Zener diode is ((V0 - VZ) / RS) - IL.

The correct option is 4)

Semiconductor Diode Question 5:

Match List I with List II

LIST I

LIST II

A.

Zener Diode

I.

Detect optical signals

B.

LED

II.

Voltage Regulator

C.

Rectifier

III.

Remote Control

D.

Photo diode

IV.

AC to DC


Choose the correct answer from the options given below:

  1. A - I, B - II, C - III, D - IV
  2. A - II, B - IV, C - I, D - III
  3. A - III, B - II, C - IV, D - I
  4. A - II, B - III, C - IV, D - I

Answer (Detailed Solution Below)

Option 4 : A - II, B - III, C - IV, D - I

Semiconductor Diode Question 5 Detailed Solution

​Explanation:

A. Zener Diode - Zener diodes are commonly used for voltage regulation. So, A matches with II (Voltage Regulator).

B. LED - LEDs are used for displays and indicators, often in remote control systems, so B matches with III (Remote Control).

C. Rectifier - A rectifier converts AC to DC, so C matches with IV (AC to DC).

D. Photo Diode - Photo diodes are used to detect optical signals, so D matches with I (Detect optical signals).

Correct Answer: Option 4) A - II, B - IV, C - I, D - III

Top Semiconductor Diode MCQ Objective Questions

Zener diode is used as:

  1. an amplifier
  2. a rectifier
  3. a oscillator
  4. voltage regulator

Answer (Detailed Solution Below)

Option 4 : a voltage regulator

Semiconductor Diode Question 6 Detailed Solution

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CONCEPT:

Zener diode: 

  • Semiconductor Diode blocks current in the reverse direction but will suffer from premature breakdown or damage if the reverse voltage applied across becomes too high.

 

F1 J.K Madhu 28.05.20 D16

EXPLANATION:

Zener diode as a voltage regulator: 

  • The Zener diode is connected with its cathode terminal connected to the positive rail of the DC supply so it is reverse biased and will be operating in its breakdown condition.
  • Resistor Rs is selected so as to limit the maximum current flowing in the circuit.

F1 J.K Madhu 28.05.20 D17

  • Zener diode is used as a voltage regulator in reverse biased mode.
  • The breakdown voltage in the Zener diode when connected in the reverse-biased is called Zener voltage. This Zener voltage so steady and constant, it has huge applications in circuits, most importantly, voltage regulation. Therefore option 4 is correct.

The device that can be used as a voltage regulator, voltage clamper and a voltage reference is __________.

  1. Zener diode
  2. Transistor
  3. IC
  4. Resistor

Answer (Detailed Solution Below)

Option 1 : Zener diode

Semiconductor Diode Question 7 Detailed Solution

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CONCEPT:

  • Zener diode: It is a highly doped p - n junction which is not damaged by high reverse current.
  • It can operate continuously, without being damaged in the region of reverse background voltage.
  • It is represented by

EXPLANATION:

  • Zener diode can be used as voltage regulator, voltage clamper and voltage reference. Therefore option 1 is correct.
  • A transistor is a device used to amplify electronic signals. Therefore option 2 is incorrect.
  • IC or integrated circuit consists of thousands of small resistors, capacitors, and transistors. It can perform as a timer, microprocessor, oscillator, amplifier, etc. Therefore option 3 is incorrect.
  • Resistors are used to reduce the flow of current. Therefore option 4 is incorrect.

The ____________ diode is fabricated by heavily doping both p- and n- sides of the junction.

  1. Light emitting
  2. Photodiodes
  3. Zener
  4. Laser

Answer (Detailed Solution Below)

Option 3 : Zener

Semiconductor Diode Question 8 Detailed Solution

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CONCEPT:

  • Zener diodes are normal PN junction diodes operating in a reverse-biased condition.
    • Working of the Zener diode is similar to a PN junction diode in forward biased condition, but the uniqueness lies in the fact that it can also conduct when it is connected in reverse bias above its threshold/breakdown voltage.
    • It is operated in a breakdown region.
  • Photo-diode: It is a light-sensing device which is used to sense the intensity of light
    • Some of the examples are the smoke detector, a receiver in tv for converting remote signals, etc.
  • Normal P-N junction diode: just like Zener diode when semiconductors of P and N-type doping is combined such devices are called p-n junction diode but unlike Zener diode, this types of diode do not work in reverse bias
  • A light-emitting diode (LED): The device which is used to produce the different intensity of light and different colour depending upon the types of mater used in making it is called LED.

Some symbols:

1) F1 J.S 30.3.20 Pallavi D6    Zener diodes

2) F1 J.S 30.3.20 Pallavi D7    Normal P-N junction

3) F1 J.S 30.3.20 Pallavi D8    A light-emitting diode (LED)

4) F1 J.S 30.3.20 Pallavi D9            Photo-diode

EXPLANATION:

  • Zener diode is used as a voltage regulator in reverse biased mode.
  • The breakdown voltage in the Zener diode when connected in the reverse-biased is called Zener voltage.
  • This Zener voltage so steady and constant, it has huge applications in circuits, most importantly, voltage regulation.
  • From the above explanation, we can see that Zener diode is fabricated by heavily doped p-side and n-side, which help it in operating in reverse bias.

So option 3 is correct.

Zener Diode is mostly used as ___________.

  1. Half-wave rectifier
  2. Full-wave rectifier
  3. Voltage Regulator
  4. LED

Answer (Detailed Solution Below)

Option 3 : Voltage Regulator

Semiconductor Diode Question 9 Detailed Solution

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Zener Diode is mostly used as Voltage Regulator.

CONCEPT:

Zener diode: A Semiconductor Diode blocks current in the reverse direction, but will suffer from premature breakdown or damage if the reverse voltage applied across becomes too high.

 

F1 J.K Madhu 28.05.20 D16

Zener diode as voltage regulator: The Zener diode is connected with its cathode terminal connected to the positive rail of the DC supply so it is reverse biased and will be operating in its breakdown condition. Resistor Rs is selected so to limit the maximum current flowing in the circuit.

F1 J.K Madhu 28.05.20 D17

EXPLANATION:

  • A Zener diode is used as a voltage regulator in reverse biased mode.
  • The breakdown voltage in the Zener diode when connected in the reverse-biased is called Zener voltage. This Zener voltage so steady and constant, it has huge applications in circuits, most importantly, voltage regulation.

So option 3 is correct.

Additional Information

  • Half wave rectifier: A half-wave rectifier is only allowing one half-cycle of an AC voltage waveform to pass, blocking the other half-cycle. Half-wave rectifiers are used to convert AC voltage to DC voltage, and only require single diodes to construct.
  • Full-wave rectifier: A full-wave rectifier converts both halves of each cycle of an alternating wave (AC signal) into a pulsating DC signal.
  • LED: A light-emitting diode is a semiconductor device that emits visible light when an electrical current passes through it.

A photodiode works on the principle of

  1. photo – voltaic effect
  2. photo - conductive effect
  3. photo – electric effect
  4. photo – thermal effect

Answer (Detailed Solution Below)

Option 2 : photo - conductive effect

Semiconductor Diode Question 10 Detailed Solution

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CONCEPT:

  • A photodiode is one type of light detector, used to convert the light into current or voltage.
  • The working principle of a photodiode is, when a photon of ample energy strikes the diode, it makes a couple of an electron-hole.
  • This mechanism is also called as the photoconductive effect. So option 2 is correct.
  • Photoconductive detectors use the increase in electrical conductivity resulting from increase in the number of free carriers generated when photons are absorbed (generation of current)

mistake point

  • User may get confused with the photoelectric effect and photoconductive effect.
  • The photoconductive effect is special case of photoelectric effect where the device is reversed biased.

If P-N junction diode is in reverse bias, then:

  1. The direction of applied voltage is same as the direction of barrier potential
  2. The direction of applied voltage is opposite as the direction of barrier potential
  3. AC voltage is applied across P-N junction diode
  4. None of these

Answer (Detailed Solution Below)

Option 1 : The direction of applied voltage is same as the direction of barrier potential

Semiconductor Diode Question 11 Detailed Solution

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CONCEPT:

Diode:

  • diode is a semiconductor device that essentially acts as a one-way switch for current.
    • It allows current to flow easily in one direction but severely restricts current from flowing in the opposite direction.

F1 J.K Madhu 01.07.20 D1

  • Forward bias and reverse bias:

 

Forward bias Reverse bias
In the forward bias, the p side of the diode is connected to the positive side of the battery and the n side is connected to the negative side of the battery.  When the p-side is connected to the negative terminal and the n-side is connected to the positive terminal of the battery, it is called reverse biased. 
The direction of the applied voltage is opposite to the junction barrier potential. Therefore, the size of the depletion region decreases. When a reverse bias is applied, free electrons are pulled away from the junction, which results in the increase of the width and resistance of the depletion region.


EXPLANATION:

Reverse bias:

  • When an external voltage (V ) is applied across the diode such that the n-side is positive and the p-side is negative, it is said to be reverse biased. The applied voltage mostly drops across the depletion region.
  • The direction of the applied voltage is the same as the direction of barrier potential. As a result, the barrier height increases, and the depletion region widens due to the change in the electric field. Hence, option 1 is correct.

What type of diode can be used as a voltage regulator?

  1. Photodiode
  2. Zener diode
  3. Light-emitting diode
  4. Solar cell

Answer (Detailed Solution Below)

Option 2 : Zener diode

Semiconductor Diode Question 12 Detailed Solution

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CONCEPT:

  • Zener diode: It is a highly doped p - n junction which is not damaged by high reverse current.
  • It can operate continuously, without being damaged in the region of reverse background voltage.
  • It is represented by

EXPLANATION:

  • When a Zener diode is operated in the reverse breakdown region, a voltage across it remains practically constant (equal to the break voltage VZ)  for a large change in the reverse current.
  • Thus based on this fact Zener diode is used as a voltage regulator.

If dopping in the P region is high then N region:

  1. depletion layer will more towards P.
  2. depletion layer will more towards N.
  3. depletion layer will remain unchanged.
  4. none of these

Answer (Detailed Solution Below)

Option 2 : depletion layer will more towards N.

Semiconductor Diode Question 13 Detailed Solution

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CONCEPT:

  • Semiconductor: Semiconductors are the materials that have a conductivity between conductors (generally metals) and non-conductors or insulators (such as ceramics).
  • Doping of semiconductor: To improve the electrical properties of semiconductors, the impurities are added to it that is called the doping of semiconductors.
  • Diode:diode is a semiconductor device that essentially acts as a one-way switch for current. It allows current to flow easily in one direction but severely restricts current from flowing in the opposite direction.

F1 J.K Madhu 01.07.20 D1

EXPLANATION:

  • In a P−N junction diode, if the P - region is heavily doped than the N region then, the depletion layer is more on the less doped side.
  • Hence, option 2 is correct.

Ripple factor of a half wave rectifier is:

  1. 1.21
  2. 0.08
  3. 0.61
  4. 2.14

Answer (Detailed Solution Below)

Option 1 : 1.21

Semiconductor Diode Question 14 Detailed Solution

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CONCEPT:

Ripple

  • ‘Ripple’ is the unwanted AC component remaining when converting the AC voltage waveform into a DC waveform. Even though we try our best to remove all AC components, there is still some small amount left on the output side which pulsates the DC waveform. This undesirable AC component is called a ‘ripple’.

Ripple factor

  • The ripple factor is the ratio between the RMS value of the AC voltage (on the input side) and the DC voltage (on the output side) of the rectifier.

\(\Rightarrow r=\frac{\sqrt{I_{rms}^{2}-I_{dc}^{2}}}{I_{dc}}\)     -----(1)

CALCULATION:

Given \(I_{rms}=\frac{I_{o}}{\sqrt{2}}\) and \( I_{dc}=\frac{I_{o}}{\pi}\)

  • rectifier is a device that converts an alternating current into a direct current. A p-n junction can be used as a rectifier because it permits current in one direction only.
  • p-n junction can be used as a rectifier because it permits current in one direction only.

By equation 1,

\(\Rightarrow r=\frac{\sqrt{I_{rms}^{2}-I_{dc}^{2}}}{I_{dc}}\)

\(\Rightarrow I_{rms}=\frac{\sqrt{\frac{I_{o}^{2}}{2}-\frac{I_{o}^{2}}{\pi^{2}}}}{\frac{I_{o}}{\pi}}\) = 1.21

  • Hence, option 1 is correct.

Additional Information

CIRCUIT DIAGRAM

Ripple factor

F1 S.B Madhu 20.01.20 D1

Half-Wave Rectifier

1.21

Diagram DMRC

      Center-Tap Full Wave Rectifier

0.48

F1 S.B Madhu 20.01.20 D3

Bridge-Type Full Wave Rectifier

0.48

The diode used in voltage regulator is:

  1. P-N diode 
  2. Photo diode 
  3. Zener diode 
  4. Tunnel diode 

Answer (Detailed Solution Below)

Option 3 : Zener diode 

Semiconductor Diode Question 15 Detailed Solution

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CONCEPT:

Zener diode:

  • A Zener diode is a semiconductor device that allows current to flow either in a forward or reverse direction.
  • Since it is highly doped, the depletion layer is very thin and has a high voltage gradient and electric field.

F9 Utkarsha S 7-5-2021 Swati D7

EXPLANATION:

  • The Zener diode will be operated in the reverse breakdown region so that the voltage will remain constant. Therefore option 3 is correct. 
  • In that region, the voltage will be equal to the breakdown voltage and this will make the Zener diode work as a voltage regulator.

Additional Information

Photo diode:

  • A photo diode is a semiconductor device that converts light into electrical current.
  • It is commonly used in remote controls to detect signals from an infrared (IR) .


Tunnel diode

  • A tunnel diode is a highly doped semiconductor diode.
  • The p-type and n-type semiconductor is heavily doped in a tunnel diode due to a greater number of impurities. Heavy doping results in a narrow depletion region.
  • When compared to a normal p-n junction diode, tunnel diode has a narrow depletion width.
  • The Fermi level moves in the conduction band on the n-side and inside the valence band on the p-side.
  • Below the Fermi level, all states are filled and above the Fermi level all states are empty

Tunnel diode is represented by the symbol

F1 P.Y Madhu 9.03.20 D10

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