Random Sequence of Alphabets MCQ Quiz - Objective Question with Answer for Random Sequence of Alphabets - Download Free PDF

Given words: BAD, FIG, ICE, NOT

Transformation Rules:

• Each vowel is changed to the letter immediately following it in the English alphabetical order.
• Each consonant is changed to the letter immediately preceding it in the English alphabetical order.

Analysis of each word and resulting cluster:

Conclusion:

From the analysis, the letter clusters with no vowels are JBF and MPS.

Thus, there are "Two" such letter clusters where no vowel appears.

Hence, the correct answer is "Option 3".

Given: ACT BUS CAR DAD

According to the question:

In each of the words, each vowel is changed to the letter immediately following it in the English alphabetical order and each consonant is changed to the letter immediately preceding in the English alphabetical order.

Now, changing each letter in the words:

ACT: A → B, C → B, T → S

BUS: B → A, U → V, S → R

CAR: C → B, A → B, R → Q

DAD: D → C, A → B, D → C

Thus, the new clusters formed are:

ACT → BBS

BUS → AVR

CAR → BBQ

DAD → CBC

In these clusters, the ones without any vowel (A, E, I, O, U) are:

BBS, BBQ, CBC

Hence, the number of letter clusters where no vowel appears is: 3

Therefore, the correct answer is "Option 3".

Given: DIE CUP BOX ASK

According to the question:

In each of the words, each vowel is changed to the letter immediately following it in the English alphabetical order and each consonant is changed to the letter immediately preceding in the English alphabetical order.

Now, changing each letter in the words:

DIE: D → C, I → J, E → F

CUP: C → B, U → V, P → O

BOX: B → A, O → P, X → W

ASK: A → B, S → R, K → J

Thus, the new clusters formed are:

DIE → CJF

CUP → BVO

BOX → APW

ASK → BRJ

In these clusters, the ones without any vowel (A, E, I, O, U) are:

CJF, BVO, APW, BRJ

Thus, 2 cluster of letter without any vowel CJF,  BRJ

Hence, the correct answer is "Option 1".

Given words: THE   MOD   CPU   RAM   SHE

According to te question, the given words are arranged in the order as they would appear in the English dictionary from left to right:

CPU   MOD   RAM   SHE   THE

So, the word that is fourth from the right is → MOD

Given words: THE   MOD   CPU   RAM   SHE

According to te question, on changing third alphabet in each of the word to next alphabet as per English alphabetical order:

THF   MOE   CPV   RAN   SHF

Thus, none of the words have more than two vowel.

The given letter clusters are,

AIN, ONK, AST, EJO

When each letter is changed to the next letter in the English alphabetical order, the words formed are

BJO, POL, BTU, FKP

From the above words, only one word doesn't have a vowel.

Hence, the correct answer is option 4).

Given words: PRIORITY and SECTOR

1^st, 4^th, 5^th and 7^th letter from the first word is: P, O, R, T 

3^rd, 5^th, and 6^th letter from the second word is: C, O, R

Combining and jumbling first and second word we get: PROCTOR

Hence, the first letter will, be P.

Given series: P M S K Q A B M N O P Q R W

1) Letters at even positions: M, K, A, M, O, Q, W

Succeeding letters: N, L, B, N, P, R, X

2) Letters at odd positions: P, S, Q, B, N, P, R

Preceding Letters: O, R, P, A, M, O, Q

New series: O, N, R, L, P, B, A, N, M, P, O, R, Q, X

Letters appearing twice in the new series: O, N, R and P

Given three-digit numbers series:

(Left) 653 831 933 476 715 (Right)

If 2 is added to the third digit of every number, the new number formed is shown below:

655 833 935 478 717

In the new number series 655, 833, and 717, are the numbers where the third digit can be exactly divided by the second digit of that number.

Hence, the correct answer is option 2).

The logic followed here is :

Given series: (Left) K B # A @ S * B Q @ R V N % & S (Right)

The element that is third from the right end is %

(Left) K B # A @ S * B Q @ R V N % & S (Right)

The element that is sixth from the left end of the given series is S

(Left) K B # A @ S * B Q @ R V N % & S (Right)

(Left) K B # A @ S * B Q @ R V N % & S (Right)

Thus, there are a total of 5 letters that are B, Q, R, V, N 

Hence, the correct answer is  "Option 2".

Given Series: ABCDEFGHIJKLMNOPQRSTUVWXYZ

Series in the reverse order: ZYXWVUTSRQPONMLKJIHGFEDCBA

Deleting alternate letters from Y in the above reverse series: Z X V T R P N L J H F D B

Therefore, the letter that divides the new series into two equal parts is N.

Hence, the correct answer is "N".

Given series: (Left) Q A Y S R E Z I L X B O P A R D I H O U K (Right)

Required pattern: Vowel → Consonant → Vowel

So, There are 3 consonants are there, each of which is immediately preceded by a vowel and also immediately followed by a vowel.

Hence, "Option 3" is the correct answer.

Mistake Points

Immediately preceded by means immediately before or to come just before.

Immediately followed by means immediately after or to come just after.

The logic followed is:

Given series- 

KDCWKDWNKGDWDHKVDWZDW

Condition to be checked:

D which are immediately followed by W but NOT immediately preceded by K.

Not K → D → W

The series are given below

KDCWKDWNKGDWDHKVDWZDW

There are three pair of word which is GDW, VDW and ZDW.

Hence, "3" is the correct answer.

Word: JUNIOR

Thus, only position of N remains unchanged.

Hence, one is the answer.

Given series:

(Left) A D 4 F @ T 5 H $ B R @ V T 6 # 7 H 6 D 8 $ % & G $ 3 C F (Right)

When all the symbols are dropped from the series,

Ninth to the left of fifth from the right → This means 14^th position to left from the right end.

(Left) A D 4 F T 5 H B R V T 6 7 H 6 D 8 G 3 C F (Right)

The letter 'B' is ninth to the left of fifth from the right.

Hence, the correct answer is option 4).