Orificemeter MCQ Quiz - Objective Question with Answer for Orificemeter - Download Free PDF

Last updated on May 22, 2025

Latest Orificemeter MCQ Objective Questions

Orificemeter Question 1:

Which of the following types of orifice is classified based on the nature of discharge?

  1. Drowned orifice
  2. Sharp-edged orifice
  3. Circular orifice
  4. Bell-mouthed orifice

Answer (Detailed Solution Below)

Option 1 : Drowned orifice

Orificemeter Question 1 Detailed Solution

Explanation:

Classification of Orifices

Orifices can be classified based on various criteria, including the shape of the orifice, the edge type, and the nature of discharge. In the given question, the classification is based on the nature of discharge, which focuses on whether the flow is free or submerged.

Analyzing the Given Options

  1. "Drowned orifice." (Correct Answer)

    • A drowned orifice, also known as a submerged orifice, occurs when the downstream water level is higher than the top of the orifice, causing the flow to be submerged. This classification is based on the nature of discharge.

    • In this case, the entire orifice is under water, and the discharge characteristics are influenced by the downstream water level.

  2. "Sharp-edged orifice." (Incorrect Answer)

    • A sharp-edged orifice is classified based on the edge type, not the nature of discharge. It has a thin edge that creates a clear, well-defined jet.

  3. "Circular orifice." (Incorrect Answer)

    • A circular orifice is classified based on its shape, not the nature of discharge. It refers to an orifice with a circular opening.

  4. "Bell-mouthed orifice." (Incorrect Answer)

    • A bell-mouthed orifice is classified based on its shape, specifically its flared or bell-shaped opening, which reduces the contraction of the jet.

Orificemeter Question 2:

The discharge through an orifice can be calculated using the formula \(\rm Q=C_dA\sqrt{2gh}\), where Q is the discharge, Cd is the discharge coefficient, A is the cross-sectional area of the orifice, g is the acceleration due to gravity, h is the head of the liquid above the orifice. If the actual measured discharge is lower than the theoretical discharge, which of the following could be true?

  1. The discharge coefficient Cd is equal to 1.
  2. The head h has been overestimated in the calculation of the theoretical discharge. 
  3. The velocity of the fluid is greater than what is predicted by the theoretical formula.
  4. The discharge coefficient Cd is less than 1 due to flow contractions and friction losses.

Answer (Detailed Solution Below)

Option 4 : The discharge coefficient Cd is less than 1 due to flow contractions and friction losses.

Orificemeter Question 2 Detailed Solution

Concept:

The actual discharge through an orifice is generally lower than the theoretical discharge due to energy losses such as:

  • Friction losses within the orifice.
  • Flow contraction (vena contracta effect) reducing the effective flow area.
  • Viscous effects in real fluids.

Theoretical discharge is given by Torricelli’s theorem:

\( Q_{\text{theoretical}} = A \sqrt{2gh} \)

The actual discharge is calculated using the discharge coefficient \( C_d \):

\( Q_{\text{actual}} = C_d A \sqrt{2gh} \)

Since real flow experiences losses, the coefficient of discharge \( C_d \) is always less than 1.

Orificemeter Question 3:

An orifice meter, with Cd = 0.61 is substituted by venturimeter with Cd = 0.98 in a pipe line carrying crude oil, having the same throat diameter as that of orifice. For the same flow rate, the ratio of pressure drops for the venturimeter and orifice meter is-

  1. \(\frac{0.61}{0.98}\)
  2. \(\left(\frac{0.61}{0.98}\right)^{2}\)
  3. \(\left(\frac{0.98}{0.61}\right)\)
  4. \(\left(\frac{0.98}{0.61}\right)^{2}\)

Answer (Detailed Solution Below)

Option 2 : \(\left(\frac{0.61}{0.98}\right)^{2}\)

Orificemeter Question 3 Detailed Solution

Explanation:
Discharge Q through a venturimeter or an orificemeter is given by

\(\begin{array}{l} Q = {C_d}\frac{{{a_1}{a_2}}}{{\sqrt {a_1^2 - a_2^2} }}\sqrt {2gh} \\ \therefore h \propto \frac{1}{{C_d^2}}\\ \therefore \frac{{{h_v}}}{{{h_o}}} = {\left( {\frac{{{C_{d,o}}}}{{{C_{d,v}}}}} \right)^2} = {\left( {\frac{{0.61}}{{0.98}}} \right)^2} \end{array}\)

Orificemeter Question 4:

Which of the following is NOT a classification of orifices?

  1. Free discharging orifices
  2. Drowned orifices
  3. Submerged orifices
  4. Blocked orifices

Answer (Detailed Solution Below)

Option 4 : Blocked orifices

Orificemeter Question 4 Detailed Solution

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Explanation:

Correct Option Analysis:

The correct option is option 4: Blocked orifices.

An orifice is a small opening or hole, typically used to control the flow of fluids, including gases and liquids. The classification of orifices is based on the conditions under which they operate, and how they manage the flow of the fluid passing through them. The correct classification of orifices includes:

  • Free Discharging Orifices: These orifices discharge fluid into the atmosphere or into a space where the pressure is relatively low, without any significant back pressure. The fluid exits the orifice freely.
  • Drowned Orifices: These orifices are fully submerged in the fluid on both sides. The fluid flow through the orifice is influenced by the pressure differential across the orifice.
  • Submerged Orifices: Similar to drowned orifices, submerged orifices are those where the exit is submerged in the fluid. The flow characteristics are determined by the difference in fluid levels and pressures on either side of the orifice.

Blocked orifices, on the other hand, are not a recognized classification of orifices. A blocked orifice would imply that there is no flow through the orifice, which defeats the purpose of having an orifice in the first place. Orifices are designed to allow controlled flow of fluid, and if an orifice is blocked, it no longer serves its functional purpose.

Therefore, option 4 is the correct answer as it does not fit within the recognized classifications of orifices.

Additional Information

To further understand the analysis, let’s evaluate the other options:

Option 1: Free discharging orifices

Free discharging orifices are a valid classification of orifices. These orifices discharge fluid into the atmosphere or an environment with minimal back pressure. The fluid exits the orifice freely, and the flow characteristics are determined by the pressure and velocity of the fluid as it exits.

Option 2: Drowned orifices

Drowned orifices are another valid classification. These orifices are fully submerged in the fluid, meaning that both the entry and exit points of the fluid are within the fluid medium. The flow is influenced by the pressure difference across the orifice and the fluid characteristics.

Option 3: Submerged orifices

Submerged orifices are also a recognized classification. In this case, the exit of the orifice is submerged in the fluid. The flow is determined by the fluid levels and pressures on both sides of the orifice. These orifices are commonly used in applications where precise control of fluid flow is required under submerged conditions.

Conclusion:

Understanding the correct classifications of orifices is crucial for applications in fluid dynamics and engineering. Orifices are designed to control and regulate fluid flow, and their classifications are based on the operational conditions under which they function. Blocked orifices are not a recognized classification because they do not permit fluid flow, which is contrary to the purpose of an orifice. Therefore, option 4 is correctly identified as not being a classification of orifices.

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Orificemeter Question 5:

A 2 m × 1.5 m tank of 6 m height is provided with a 100 mm diameter orifice at the center of its base. The orifice is plugged and the tank is filled up to 5 m height. Consider the average value of discharge coefficient as 0.6 and acceleration due to gravity (g) as 10 m/s2. After unplugging the orifice, the time (in seconds) taken for the water level to drop from 5 m to 3.5 m under free discharge condition is ___________. (rounded off to 2 decimal places).

Answer (Detailed Solution Below) 103.985

Orificemeter Question 5 Detailed Solution

Explanation:

As per given data:

  • Tank dimensions: 2 m × 1.5 m

  • Tank height: 6 m

  • Orifice diameter: 100 mm = 0.1 m

  • Initial water level: 5 m

  • Final water level: 3.5 m

  • Discharge coefficient (Cₓ): 0.6

  • Acceleration due to gravity (g): 10 m/s²

qImage6729ec05074c55aa23f3a92b1-5-2025 IMG-913 Ankit -25

Let at any instant depth of liquid in the tank is 'h' m and in time (dt), the depth falls by (-dh)

qImage6729ec05074c55aa23f3a92d1-5-2025 IMG-913 Ankit -26

Q.dt = A0(-dh) 

\(\Rightarrow\left(C_d \cdot\left(\frac{\pi d^2}{4}\right) \sqrt{2 g h}\right) d t=A_0(-d h)\)

\(t=\int d t=\frac{A_0}{C_d \cdot \frac{\pi d^2}{4} \sqrt{2 g}} \int_{H_1}^{H_2}\left(\frac{-d H}{\sqrt{h}}\right) \)

\(t=\frac{A_0}{C_d \cdot \frac{\pi d^2}{4} \sqrt{2 g}}\left[2\left(\sqrt{H_1}-\sqrt{H_2}\right)\right]\)

\(t=\left[\frac{2 \times 1.5 m^2}{0.6 \times \frac{\pi}{4}(0.1)^2 m^2 \sqrt{2 \times 10 \frac{m}{s^2}}} \times 2(\sqrt{5}-\sqrt{3.5}) \mathrm{m}^{1 / 2}\right] \mathrm{sec} \)

t = 103.985 sec

Top Orificemeter MCQ Objective Questions

The Cd value of an orifice of d/D = 0.5 (d = diameter of orifice and D = diameter of the pipe) lies in the range ______.

  1. 0.95 to 0.98 
  2. 0.60 to 0.62
  3. 0.81 to 0.94 
  4. 0.70 to 0.80

Answer (Detailed Solution Below)

Option 2 : 0.60 to 0.62

Orificemeter Question 6 Detailed Solution

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Explanation:

Coefficient of discharge is the ratio of actual discharge to the theoretical discharge.

\(\rm C_d=\frac{Actual \;discharg}{Theoretical\:discharge}\)

Coefficient of discharge for various devices are:

⇒ Venturimeter – 0.95 to 0.98

 Orifice meter – 0.62 to 0.65

 Nozzle  – 0.93 to 0.98

A fluid flows through an orifice of an area 0.4 m2 with an actual discharge of 400 l/s. If the theoretical velocity of flow through the orifice is 2 m/s, what is the coefficient of discharge?

  1. 0.71
  2. 0.68
  3. 0.50
  4. 0.56

Answer (Detailed Solution Below)

Option 3 : 0.50

Orificemeter Question 7 Detailed Solution

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Concepts:

The coefficient of discharge (Cd) is the ratio of the actual discharge (Qa) to theoretical discharge (Qth) .

The actual discharge is the discharge obtained when all the looses through orifice or pipe flow are considered. While, theoretical discharge is the discharge obtained under ideal conditions i.e. no loss is considered.

The  theoretical discharge is given as:

Qth = A × Vth

Vth is the theoretical velocity of flow

Calculations:

Given: Vth = 2 m/s; A = 0.4 m2

So, Qth = 0.4 × 2 = 0.8 m3/s  or 800 l/s

∴ Cd = 400/800

Cd = 0.5

Other important Coefficients:

1. Coefficient of velocity is the ratio of actual velocity to theoretical velocity.

2. Coefficient of contraction is the ratio of cross-section area at vena-contracta to original cross- sectional area.

The value of the coefficient of velocity for sharp-edged orifices is

  1. 0.41
  2. 0.98
  3. 0.85
  4. 0.66

Answer (Detailed Solution Below)

Option 2 : 0.98

Orificemeter Question 8 Detailed Solution

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Explanation:

Coefficient of velocity:

It is defined as the ratio of the actual velocity of the jet at vena contracta V to the theoretical velocity Vth.

Experimentally it is determined by using the following relation

F1 Krupalu Anil 30.01.21 D12

\({C_V} = \sqrt {\frac{{{x^2}}}{{4\;y\;h}}} \)

where x = Horizontal distance

y = vertical distance

h = constant head water

Generally, the value of Cv varies from 0.95 to .99 for different orifices depending upon their size, shape, head etc.

for sharp edged orifices the value of Cv is 0.98.

Types of tubes   Cc Cv
    Rounded      1   0.98
Sharp-edged  0.62 0.98
Short tube  1 0.8
Borda tube 0.52 0.98

Two small circular orifice of diameters d1 and d2, respectively, are placed on the side of a tank at depths of 25 cm and 1 m below a consistently maintained surface of water. If the discharges through the orifices are the same, what is the ratio of the diameter d1 to d2

  1. 1/2
  2. 1/√2
  3. 2
  4. √2

Answer (Detailed Solution Below)

Option 4 : √2

Orificemeter Question 9 Detailed Solution

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Concept:

Discharge through a circular orifice is given by;

\(Q = {C_d}a\sqrt {2gh} \)

Where, a = Area of orifice

h = Head above the surface

Calculation:

Given,

Discharge through the orifices are same

h1 = 25 cm, h2 = 1 m = 100 cm

∵ we know that, \(Q = {C_d}a\sqrt {2gh} \)

and, Q1 = Q2

⇒ \({C_d}{a_1}\sqrt {2g{h_1}} = {C_d}{a_2}\sqrt {2g{h_2}} \)

⇒ \(\frac{\pi }{4} \times d_1^2\sqrt {{h_1}} = \frac{\pi }{4} \times d_2^2\sqrt {{h_2}} \)

\(\frac{{d_1^2}}{{d_2^2}} = \sqrt {\frac{{{h_2}}}{{{h_1}}}} = \sqrt {\frac{{100}}{{25}}} = 2\)

\(\frac{{{d_1}}}{{{d_2}}} = \sqrt 2 \)

When an orifice for flow measurement in a pipe is replaced by a venturimeter, the pressure drop for the same flow is expected to

  1. remain same
  2. increase
  3. decrease
  4. None of these

Answer (Detailed Solution Below)

Option 3 : decrease

Orificemeter Question 10 Detailed Solution

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Explanation:

  • As the fluid flows pressure drops along the direction of flow due to losses. Hence the more the losses along the flow the more will we be the pressure drop.
  • Coefficient of discharge (Cd) is the measure of flow efficiency. It means higher the value of  Cd lesser will be the losses.
  • Venturimeter is more efficient than the Orifice meter. Hence the coefficient of discharge is higher for Venturimeter than for Orifice meter.

Now,

\(Pressure\ drop\ (Δ P) ∝ \frac{1}{Coefficient\ of\ discharge\ (C_d)}\)

∵ (Cd)venturimeter  > (Cd)orifice meter 

∴ (ΔP)venturimeter < (ΔP)orific meter

Hence if Orific is replaced by a Venturimeter in a pipe then the pressure drop will decrease.

Additional Information

Venturimeter:

  • A venturi meter is a device used for measuring the rate of flow of a fluid of a liquid flowing through a pipe
  • The venturi meter always have a smaller convergent portion and larger divergent portion
  • The size of the venturi meter is specified by its pipe diameter as well as throat diameter.

  • This is done to ensures a rapid converging passage and a gradual diverging passage in the direction of flow to avoid the loss of energy due to the separation
  • In the course of flow through the converging part, the velocity increases in the direction of flow according to the principle of continuity, while the pressure decreases according to Bernoulli’s theorem
  • The velocity reaches its maximum value and pressure reaches its minimum value at the throat
  • Subsequently, a decrease in the velocity and an increase in the pressure take place in course of flow through the divergent part
  • The angle of convergence ≈ 20°, Angle of divergence = 6° - 7°. It should be not greater than 7° to avoid flow separation

Orifice meter:

  • An orifice meter provides a simpler and cheaper arrangement for the measurement of flow through a pipe.
  • An orifice meter is essentially a thin circular plate with a sharp-edged concentric circular hole in it.

SSC JE MEchanical 2 9

Cd is defined as the ratio of the actual flow and the ideal flow and is always less than one. 

For orifice meter, the coefficient of discharge Cd depends on the shape of the nozzle, the ratio of pipe to nozzle diameter and the Reynolds number of the flow.

An orifice meter, having an orifice of diameter ‘d’ is fitted in a pipe of diameter D. For this orifice meter, what is the coefficient of discharge Cd?

  1. A function of Reynolds number only
  2. A function of d/D only
  3. A function of d/D and Reynolds number
  4. Independent of d/D and Reynolds number

Answer (Detailed Solution Below)

Option 3 : A function of d/D and Reynolds number

Orificemeter Question 11 Detailed Solution

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An orifice meter provides a simpler and cheaper arrangement for the measurement of flow through a pipe. An orifice meter is essentially a thin circular plate with a sharp-edged concentric circular hole in it.

SSC JE MEchanical 2 9

Cd is defined as the ratio of the actual flow and the ideal flow and is always less than one. 

For the orifice meter, the coefficient of discharge Cd depends on the shape of the nozzle, the ratio of pipe to nozzle diameter and the Reynolds number of the flow.

Important Points

The coefficient of discharge is shows as the losses inflow. Since in laminar flow losses are less and in turbulent losses is more hence the value of the coefficient of discharge also varies with the type of flow. As we know Reynold number shows the type of flow occurring hence we can say that the coefficient of discharge also depends upon the Reynold number.

The actual discharge of liquid through an orifice is determined by multiplying ideal discharge by a factor called coefficient of discharge. The coefficient of discharge is given by ________.

  1. \(\frac{\text { Discharge }}{\text { Velocity }}\)
  2. \(\frac{\text { Theoretical discharge }}{\text { Actual discharge }}\)
  3. \(\frac{\text { Actual discharge }}{\text { Theoretical discharge }}\)
  4. \(\frac{\text { Actual discharge }}{\text { Velocity }}\)

Answer (Detailed Solution Below)

Option 3 : \(\frac{\text { Actual discharge }}{\text { Theoretical discharge }}\)

Orificemeter Question 12 Detailed Solution

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Explanation:

Orifice meter:

  • An orifice meter is a cheap device for discharge measurement.
  • The coefficient of discharge (Cd) is defined as the ratio of actual discharge to the ideal discharge.

 Cd =\(\frac{\text { Actual discharge }}{\text { Theoretical discharge }}\) 

  • The value of Ca carries between 0.61 to 0.65.

SSC JE MEchanical 2 9

A venturi meter is preferable to orifice meter because

  1. it is cheaper
  2. it is more convenient
  3. energy loss is less
  4. it is easy to assemble

Answer (Detailed Solution Below)

Option 3 : energy loss is less

Orificemeter Question 13 Detailed Solution

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Explanation:

Orifice meter

Venturimeter

The orifice meter is used for measuring the rates of flow in incompressible fluid only.

Venturimeter is used for measuring rates of flow in both incompressible and compressible fluids.

Simple in construction

Relatively complex in construction

Relatively  cheap

Expensive

Head losses are more

Head losses are insignificant

Energy loss is more

Energy loss is less

Coefficient of discharge is about 0.61

Coefficient of discharge is 0.98

Low space requirement

Occupies more space

The head of water over an orifice of area 0.1 m2 is 5 m. Cd= 0.4 The actual discharge in m3 per second if (assume g 10m/s2) is

  1. 0.4
  2. 0.2
  3. 4
  4. 2

Answer (Detailed Solution Below)

Option 1 : 0.4

Orificemeter Question 14 Detailed Solution

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Concept:

Coefficient of discharge (Cd) is defined as:

\(C_d=\frac{Q_{actual}}{Q_{theoretical}}\)

Theoretical discharge (Qtheoretical) can be calculated by:

Qtheoretical = Area of orifice × velocity of flow

Velocity of flow (V) can be calculated by:

\(V = \sqrt{2gh}\)

where h is head of fluid over the orifice

Calculation:

Given:

h = 5 m, Area = 0.1 m2, Cd = 0.4

Velocity of flow is:

\(V = \sqrt{2gh}\)

\(V = \sqrt{2×10×5}=10~m/s\)

Theoretical discharge (Qtheoreticalis:

Qtheoretical = Area of orifice × velocity of flow

Qtheoretical = 0.1 × 10 = 1 m3/s

We know that,

\(C_d=\frac{Q_{actual}}{Q_{theoretical}}\)

Actual discharge is:

Qactual = Cd × Qtheoretical 

Qactual = 0.4 × 1 = 0.4 m3/s

The distance of vena contracta from the orifice is approximately

  1. 3/4 diameter of the orifice
  2. 1/4 diameter of the orifice
  3. 2/3 diameter of the orifice
  4. 1/2 diameter of the orifice

Answer (Detailed Solution Below)

Option 4 : 1/2 diameter of the orifice

Orificemeter Question 15 Detailed Solution

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Explanation:

Vena contracta:

  • The section of least cross-section and hence of maximum contraction is called vena contracta.
  • Since the area is minimum, the velocity is maximum at the vena contracta.
  • It occurs about one half orifice diameter away from the downstream edge of the orifice.
  • Formation of vena contracta is caused by the change in direction of motion of the liquid particles approaching the orifice.
  • Beyond vena contracta, the streamline becomes parallel to each other.

SSC JE ME Fluid Mechanics (31-60) images 11

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