Nodal Analysis MCQ Quiz - Objective Question with Answer for Nodal Analysis - Download Free PDF

Last updated on Jun 11, 2025

Latest Nodal Analysis MCQ Objective Questions

Nodal Analysis Question 1:

The nodal method of circuit analysis is based on

  1. KCL and KVL
  2. KCL, KVL and Ohm's Law
  3. KCL and Ohm's Law
  4. KVL and Ohm's Law

Answer (Detailed Solution Below)

Option 3 : KCL and Ohm's Law

Nodal Analysis Question 1 Detailed Solution

Explanation:

Nodal Method of Circuit Analysis

Definition: The nodal method of circuit analysis, also known as nodal analysis, is a technique used to determine the voltage at various nodes in an electrical circuit. It is based on Kirchhoff's Current Law (KCL) and Ohm's Law. This method is particularly useful for analyzing circuits with multiple nodes and components.

Working Principle:

Nodal analysis relies on the following principles:

  • Kirchhoff's Current Law (KCL): States that the algebraic sum of currents entering and leaving a node is zero. This law is used to write equations at each node in the circuit.
  • Ohm's Law: Relates the voltage across a resistor to the current flowing through it and its resistance (V = IR). This law helps express currents in terms of voltages and resistances.

By combining KCL and Ohm's Law, nodal analysis allows us to systematically solve for the unknown node voltages in the circuit.

Steps for Nodal Analysis:

  1. Identify all nodes: Assign a reference node (ground) and label the remaining nodes with variables representing their voltages.
  2. Apply KCL at each non-reference node: Write equations expressing the sum of currents entering and leaving the node as zero.
  3. Use Ohm's Law: Replace the currents in the KCL equations with expressions in terms of voltages and resistances.
  4. Solve the system of equations: Solve the resulting simultaneous equations to find the node voltages.

Advantages:

  • Simplifies complex circuit analysis by focusing on node voltages rather than branch currents.
  • Efficient for circuits with multiple components connected in parallel.
  • Provides a systematic approach to solving electrical circuits.

Disadvantages:

  • May require solving a large system of simultaneous equations for circuits with many nodes.
  • Not as intuitive as mesh analysis for circuits with many series components.

Applications:

  • Nodal analysis is widely used in electrical engineering for circuit design and analysis.
  • It is particularly useful for analyzing circuits with operational amplifiers, resistors, capacitors, and inductors.

Correct Option Analysis:

The correct option is:

Option 3: KCL and Ohm's Law.

This option accurately describes the basis of nodal analysis. Kirchhoff's Current Law (KCL) is used to write equations at each node, and Ohm's Law is used to express currents in terms of voltages and resistances. Together, these principles form the foundation of the nodal method.

Additional Information

To further understand the analysis, let’s evaluate the other options:

Option 1: KCL and KVL.

This option is incorrect because nodal analysis does not directly use Kirchhoff's Voltage Law (KVL). While KVL is essential for other methods like mesh analysis, nodal analysis exclusively relies on KCL and Ohm's Law.

Option 2: KCL, KVL, and Ohm's Law.

This option is also incorrect because the nodal method does not require the use of KVL. Although Ohm's Law is involved, KVL is unnecessary for nodal analysis. Including KVL in this context adds confusion and is not accurate.

Option 4: KVL and Ohm's Law.

This option is incorrect because nodal analysis does not use Kirchhoff's Voltage Law (KVL). KVL is used in mesh analysis, not nodal analysis, making this option irrelevant to the nodal method.

Conclusion:

Nodal analysis is a powerful technique for solving electrical circuits, especially those with multiple nodes. By relying on Kirchhoff's Current Law (KCL) and Ohm's Law, it provides a systematic approach to determine node voltages. Understanding the distinction between nodal and mesh analysis, as well as the principles involved, is essential for effectively analyzing and designing electrical circuits.

Nodal Analysis Question 2:

The nodal method of circuit analysis is based on

  1. KVL and ohms law  
  2. KVL and KCL 
  3. KCL and ohms law
  4. Thevenins theorem

Answer (Detailed Solution Below)

Option 3 : KCL and ohms law

Nodal Analysis Question 2 Detailed Solution

Explanation:

Nodal Method of Circuit Analysis

Definition: The nodal method (or node-voltage method) is a systematic technique in electrical circuit analysis that is used to determine the voltages at various nodes of an electrical circuit. It is based on Kirchhoff’s Current Law (KCL) and Ohm’s Law. This method assumes that the sum of currents entering and leaving a node is zero, which is the essence of KCL, and utilizes Ohm’s Law to relate voltages and currents through resistors and other circuit elements.

Working Principle:

1. In the nodal method, a node is defined as a point in a circuit where two or more circuit elements meet. Each node in the circuit (except the reference node) is assigned a voltage with respect to a reference (ground) node.

2. Kirchhoff's Current Law (KCL) is applied at each non-reference node, and the algebraic sum of all currents entering and leaving the node is set to zero.

3. Ohm’s Law is then used to express the currents in terms of the node voltages and the circuit element values (e.g., resistance, admittance).

4. The resulting equations are solved simultaneously to find the node voltages. Once the node voltages are known, other circuit parameters such as branch currents or power can be calculated.

Steps to Solve Using the Nodal Method:

  1. Select the reference node: This node is usually chosen as the ground node, and its voltage is set to zero.
  2. Assign node voltages: Assign a variable for the voltage at each node (except the reference node).
  3. Apply KCL: Write KCL equations for each node in terms of the node voltages. For each branch connected to a node, express the current using Ohm’s Law.
  4. Solve the equations: Solve the resulting set of simultaneous linear equations to determine the node voltages.

Advantages:

  • Efficient for circuits with many nodes and fewer voltage sources, as it reduces the number of equations to solve.
  • Provides a systematic approach to analyzing even complex circuits.
  • Directly determines the voltages at various nodes, which can be used to calculate other circuit parameters.

Disadvantages:

  • May involve solving a large number of equations for circuits with many nodes, leading to computational complexity.
  • Requires careful identification and labeling of nodes to avoid errors in the equations.

Applications: The nodal method is widely used in electrical engineering for analyzing circuits in power systems, electronics, and communication systems. It is particularly useful for analyzing AC circuits with sinusoidal signals, where impedances replace resistances in the equations.

Correct Option Analysis:

The correct option is:

Option 3: KCL and Ohm’s Law

The nodal method fundamentally relies on Kirchhoff’s Current Law (KCL) to set up the equations at each node. KCL ensures that the sum of currents entering and leaving a node is zero. Ohm’s Law is then used to express the currents in terms of the voltages and resistances (or impedances) in the circuit. This combination of KCL and Ohm’s Law forms the basis of the nodal analysis technique.

Additional Information

To further understand the analysis, let’s evaluate the other options:

Option 1: KVL and Ohm’s Law

This option is incorrect because the nodal method does not use Kirchhoff’s Voltage Law (KVL). Instead, it uses Kirchhoff’s Current Law (KCL) to set up the equations at the nodes. While Ohm’s Law is indeed used in the nodal method, the absence of KCL in this option makes it incorrect.

Option 2: KVL and KCL

This option is incorrect because the nodal method does not directly involve Kirchhoff’s Voltage Law (KVL). While KVL is a fundamental law of circuit analysis, it is not explicitly used in the nodal method. The nodal method primarily relies on KCL and Ohm’s Law.

Option 4: Thevenin’s Theorem

This option is incorrect because Thevenin’s theorem is a separate circuit analysis technique used to simplify a circuit into an equivalent circuit with a single voltage source and series resistance. It is not used in the nodal method.

Conclusion:

The nodal method of circuit analysis is a powerful and systematic technique for determining node voltages in an electrical circuit. It is based on Kirchhoff’s Current Law (KCL) and Ohm’s Law, which together form the foundation of this method. By understanding the principles of KCL and Ohm’s Law, engineers can efficiently analyze even complex circuits. The other options are incorrect as they either involve laws or techniques not used in the nodal method or fail to include the essential components of the method.

Nodal Analysis Question 3:

In the frequency domain network having 'n - principal' nodes one of them is designated as the reference node and we require ________ node voltage equation to solve for the desired result.

  1. (n - 2)
  2. n
  3. (n - 3)
  4. (n - 1)

Answer (Detailed Solution Below)

Option 4 : (n - 1)

Nodal Analysis Question 3 Detailed Solution

The correct answer is (n - 1).

Key Points

  • In a frequency domain network with 'n - principal' nodes, one node is designated as the reference node or ground.
  • The reference node is crucial for measuring the voltage at other nodes with respect to it.
  • To solve for the desired results, we require (n - 1) node voltage equations.
  • This is because we have 'n' nodes in total, and one of them is used as the reference, leaving us with (n - 1) nodes for which we need to find the voltages.
  • In network analysis, the node voltage method is a fundamental technique where the number of node voltage equations is always (n - 1) for a network with 'n' nodes.
  • The node voltage method simplifies the analysis of complex circuits by reducing the number of equations needed to solve for unknown voltages.
  • It is important to correctly designate the reference node to ensure accurate and consistent results in the analysis.

 Additional Information

  • Reference Node
    • The reference node, also known as the ground node, is a point in the circuit that is assumed to have a voltage of zero.
    • It is used as a common return path for current and a reference point for measuring other voltages in the circuit.
    • Choosing the correct reference node simplifies the analysis and calculation of node voltages.
  • Node Voltage Method
    • The node voltage method involves writing Kirchhoff's Current Law (KCL) for each node except the reference node.
    • This method reduces the complexity of solving circuit equations by focusing on node voltages rather than branch currents.
    • It is particularly useful for analyzing circuits with multiple nodes and components.
  • Kirchhoff's Current Law (KCL)
    • KCL states that the sum of currents entering a node is equal to the sum of currents leaving the node.
    • This law is fundamental in network analysis and is used to derive the node voltage equations.
    • By applying KCL at each node (except the reference node), we can form a system of linear equations to solve for the node voltages.

Nodal Analysis Question 4:

Find the node voltage V:

F2 Savita ENG 21-3-24 D1

  1. 6 V
  2. 12 V
  3. 4.25 V
  4. 3 V

Answer (Detailed Solution Below)

Option 3 : 4.25 V

Nodal Analysis Question 4 Detailed Solution

The correct answer is option"3".

Solution;-

F2 Savita ENG 21-3-24 D1

Applying nodal analysis at node \(V_A\) -

\(\frac{V_A-12}{49}+\frac{V_A}{24}+\frac{V_A-6}{80}=0\) ......(i)

Solving eqn (i) We get,

\(V_A\) = 4.29 volts

But in the given options only the value near to 4.29 is 4.25 volts.

Nodal Analysis Question 5:

If a 12Ω resistor draws a current of 1A as shown in the figure, the value of resistance R is-

F1 Eng Arbaz 6-2-24 D2

  1. 4 Ω
  2. 6 Ω
  3. 8 Ω
  4. 18 Ω

Answer (Detailed Solution Below)

Option 2 : 6 Ω

Nodal Analysis Question 5 Detailed Solution

Calculation:

F1 Eng Arbaz 6-2-24 D2

Let the voltage across the 12 ohm resistance be "V" Volts.

Let the current flowing through resistance "R" be "I"

Applying the KCL across the node voltage "V" we get,

2 = 1 + I

I = 1 A.

The voltage "V" can be calculated as 

\(\frac{V}{12} = 1 \)

V = 12 volts.

The current flowing through "R" can be calculated as

\(\frac{V -6}{R} = 1\)

putting the value of "V" we get value of "R" as

R = 6 Ω

Top Nodal Analysis MCQ Objective Questions

In nodal analysis, the preferred reference node is a node that is connected to

1. ground

2. many parts of the network

3. the highest voltage source

Which of the above is/are correct?

  1. 1 only
  2. 1 & 2 only
  3. 3 only
  4. 1, 2 and 3

Answer (Detailed Solution Below)

Option 2 : 1 & 2 only

Nodal Analysis Question 6 Detailed Solution

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In the nodal analysis, the preferred reference node is

  • A node with the largest number of elements connected to it.
  • A node which is connected to the maximum number of voltage sources, or
  • A node of symmetry


Note:

The preferred reference node is usually necessarily connected to the ground.

What will be the values of Vs and is respectively in the circuit shown below?

F29 Shubham B 19-4-2021 Swati D017

  1. 14 V, -1 A
  2. -14 V, -1 A
  3. 14 V, 1 A
  4. -14 V, 1 A

Answer (Detailed Solution Below)

Option 1 : 14 V, -1 A

Nodal Analysis Question 7 Detailed Solution

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Concept:

There are two types of Kirchoff’s Laws:

Kirchoff’s first law (KCL):

  • This law is also known as junction rule or current law (KCL). According to it the algebraic sum of currents meeting at a junction is zero i.e. Σ i = 0.

F2 P.Y Madhu 16.04.20 D 3

  • In a circuit, at any junction, the sum of the currents entering the junction must be equal to the sum of the currents leaving the junction i.e., i1 + i3 = i2 + i4
  • This law is simply a statement of “conservation of charge” as if current reaching a junction is not equal to the current leaving the junction, the charge will not be conserved.

 

Kirchoff’s second law (KVL):

  • This law is also known as loop rule or voltage law (KVL) and according to it “the algebraic sum of the changes in potential in the complete traversal of a mesh (closed-loop) is zero”, i.e. Σ V = 0.
  • This law represents “conservation of energy” as if the sum of potential changes around a closed loop is not zero, unlimited energy could be gained by repeatedly carrying a charge around a loop.
  • If there are n meshes in a circuit, the number of independent equations in accordance with the loop rule will be (n - 1).


Calculation:

F29 Shubham B 19-4-2021 Swati D017

Apply KVL to the outer loop,

- VS + 2× 2 + 10 = 0 

VS = 14 V

Apply KCL at node,

\(2 = {i_s} + \frac{{10 - 5}}{5} + \frac{{10}}{5}\)

\(2 = {i_s} + \frac{{15}}{5}\)

\(2 = {i_s} + 3\)

\({i_s} = - 1\;A\)

If the network has a/an ________ between two nodes, the concept of Supernode is used instead of nodal analysis.

  1. voltage source
  2. dependent current source
  3. independent current source
  4. resistor

Answer (Detailed Solution Below)

Option 1 : voltage source

Nodal Analysis Question 8 Detailed Solution

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Super node:

If a voltage source is connected between two non-reference nodes, then we combine the two nodes as to yield super node.

Example:

F1 U.B M.P 22.07.19 D 2

In the above circuit diagram, V1 and V2 forms supernode.

Note: Always apply mesh analysis of the node

Super mesh:

If a current source is present at the common boundary of two meshes, then we create a super mesh by avoiding the current source and any element connected to it in series.

Example:

quesImage2663

In the above circuit diagram, there is a current source in between two mesh and hence it forms a super mesh.

Note: Always apply nodal analysis at super mesh.

Determine the voltmeter reading in the given circuit.

F8 Jai Prakash 29-12-2020 Swati D13

  1. +15 V
  2. 7.5 V
  3. +30 V
  4. -30 V

Answer (Detailed Solution Below)

Option 2 : 7.5 V

Nodal Analysis Question 9 Detailed Solution

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F12 Jai Prakash 2-2-2021 Swati D26

Consider node ‘a’ as mentioned above,

Assume voltage at node ‘a’ as Va,

Apply KCL at node ‘a’, (assuming all currents are leaving the node)

\(\frac{{{V_a}}}{{20}} + 0.25 + \frac{{\left( {{V_a} - 80{i_1}} \right)}}{{60}} = 0\)

\(\frac{{3{\rm{Va\;}} + {\rm{\;}}15{\rm{\;}} + {\rm{\;}}{\rm{Va\;}}-{\rm{\;}}80{{\rm{i}}_1}}}{{60}}{\rm{ = 0}}\)

3Va + 15 + Va – 80 i1 = 0

4Va + 15 = 80 i1   -----(1)

From the circuit we can say,

V/ 20 = - i1

Va = - 20 i1

∴ equation(1) reduces as

4 × (- 20 i1) + 15 = 80 i1

\({I_{1\;}} = \frac{{15}}{{160{\rm{ }}}} A\)

Let, the voltage reads by the voltmeter = V0

It is the voltage value of the dependent source.

V0  = 80 i1

\({{\rm{V}}_0}{\rm{\;}} = {\rm{\;}}80{\rm{\;}} \times \frac{{15}}{{160}}\)

V0  = 7.5 V

The value of current I in the following circuit is shown in fig.

F1 Koda 7-2-22 Savita D2

  1. 2.45 Amp.
  2. 1.45 Amp.
  3. 2.40 Amp.
  4. 1.40 Amp.

Answer (Detailed Solution Below)

Option 4 : 1.40 Amp.

Nodal Analysis Question 10 Detailed Solution

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Concept:

 

Nodal Analysis:

  • Nodal Voltage Analysis uses the “Nodal” equations of Kirchhoff’s first law to find the voltage potentials around the circuit. So by adding together all these nodal voltages the net result will be equal to zero.
  • If there are “n” nodes in the circuit there will be “n-1” independent nodal equations and these alone are sufficient to describe and hence solve the circuit.
  • At each node point write down Kirchhoff’s first law equation(KCL), that is: “the currents entering a node are exactly equal in value to the currents leaving the node” then express each current in terms of the voltage across the branch using Ohm's law.
  • So the nodal analysis is primarily based on the application of KCL and Ohm's law.
  • For “n” nodes, one node will be used as the reference node and all the other voltages will be referenced or measured with respect to this common node


Calculation:

F1 Koda 7-2-22 Savita D2

From the above circuit,

V = 20 - 2 I        ------- (i) 

Apply KCL at node,

I + 2 = (20 - 2 I - 5I) / 3

3I + 6 = 20 - 7 I

⇒ 10 I = 14

I = 1.4 A

Find total power consumed in the circuit given-

F1 Shubham Madhu 06.08.2021 D15

  1. 266.25 W
  2. 261.5 W
  3. 264 W
  4. 268 W

Answer (Detailed Solution Below)

Option 1 : 266.25 W

Nodal Analysis Question 11 Detailed Solution

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Concept:

Tellegen’s theorem:

  • According to Tellegen’s theorem, the summation of instantaneous powers for the n number of branches in an electrical network is zero.
  • Let n number of branches in an electrical network have I1, I2, I3, ….. In respective instantaneous currents through them.
  • These branches have instantaneous voltages across them are V1, V2, V3, ….. Vn respectively.
  • According to Tellegen’s theorem, \(\mathop \sum \limits_{k = 1}^n {V_k}.{I_k} = 0\)
  • ∑ power delivered = ∑ power absorbed
  • It is based on the conservation of energy.
  • It is applicable to both linear and non-linear circuits.

 

Calculation:

F1 Koda Ravi 22.09.21 D1 Corrected

Apply KCL at node 1

\(I_1=\frac{V_1}{1}+\frac{V_1-V_2}{0.5}\)

\(\frac{15-V_1}{1}=\frac{V_1}{1}+\frac{V_1-V_2}{0.5}\)

7.5 - 0.5 V1 = 0.5 V1 + V1 - V2

7.5 = 2 V1 - V2   -------  (1)

Apply KCL at node 2

\(I_2=\frac{V_2}{2}+\frac{V_2-V_1}{0.5}\)

\(\frac{20-V_2}{1}=\frac{V_2}{2}+\frac{V_2-V_1}{0.5}\)

20 = 3.5 V2 - 2 V1 --------  (2)

By solving 1 and 2 we get

V2 = 11 V and V1 = 9.25 V

I1 = 5.75 A and I2 = 9 A

Power delivered by 15 V source = 15 × 5.75 = 86.25 W

Power delivered by 20 V source = 20 × 9 = 180 W

By Tellegon's theorem 

Total power consumed = total power delivered = 180 + 86.25 = 266.25 W

Value of R in Ω

F1 Shubham Madhu 06.08.2021 D21

  1. 10 Ω
  2. 20 Ω
  3. 30 Ω
  4. 40 Ω

Answer (Detailed Solution Below)

Option 2 : 20 Ω

Nodal Analysis Question 12 Detailed Solution

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The given circuit can easily be solved by using Nodal Analysis:

Procedure:

1. Identified the number of nodes in the circuit along with the reference node.

2. Identified the direction of current (incoming or outgoing) to each node except the reference node.

3. Apply KCL to each node except the reference node.

4. Solved the KCL equation.

Application:

The given circuit can be drawn as,

F1 Nakshatra  23-09-21 Savita D15

Apply KCL at node A,

I1 = I2 + 2 .... (1)

Let the voltage at node A = V

Hence,

\(I_1=\frac{100-V}{10}\)

\(I_2=\frac{V}{10}\)

\(2=\frac{V}{R}\)

\(\rightarrow R=\frac{V}{2}\) .... (2)

From equation (1),

\(\frac{100-V}{10}=\frac{V}{10}+2\)

or, \(10-2=\frac{2V}{10}\)

or, 2V = 80

or, V = 40 volts

From equation (2),

R = 40/2 = 20 Ω

Find Ib?

F3 Madhuri Engineering 24.03.2022 D1 V2

  1. -3 mA
  2. 3 mA
  3. 0.67 mA
  4. -0.67 mA

Answer (Detailed Solution Below)

Option 1 : -3 mA

Nodal Analysis Question 13 Detailed Solution

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Nodal Analysis:

  • Nodal Voltage Analysis uses the “Nodal” equations of Kirchhoff’s first law to find the voltage potentials around the circuit. So by adding together all these nodal voltages the net result will be equal to zero.
  • If there are “n” nodes in the circuit there will be “n-1” independent nodal equations and these alone are sufficient to describe and hence solve the circuit.
  • At each node point write down Kirchhoff’s first law equation(KCL), that is: “the currents entering a node are exactly equal in value to the currents leaving the node” then express each current in terms of the voltage across the branch using Ohm's law.
  • So the nodal analysis is primarily based on the application of KCL and Ohm's law.
  • For “n” nodes, one node will be used as the reference node and all the other voltages will be referenced or measured with respect to this common node.

 

Let a network and find voltage V using nodal analysis

F2 U.B M.P 24.09.19 D 3

Applying nodal analysis at node V

\(\frac{{V - {V_1}}}{{{R_1}}} + \frac{{V - {V_2}}}{{{R_2}}} + \frac{{V - {V_3}}}{{{R_3}}} = 0\)

Explanation:

Apply Nodal At Va;

F1 Tapesh 30-9-2020 Swati D8

\(\frac{{{V_a} - 3}}{1} + \frac{{{V_a}}}{1} + \frac{{{V_a} - 2\;{V_a}}}{1} = 0\)

Va + Va + Va – 2Va = 3

Va = 3V

Now,

\({i_b} = \frac{{{V_a} - 2{V_a}}}{{1k}} = \frac{{3 - 6}}{1} = - 3\;mA\)

Calculate the sum of branches and nodes in the circuit shown below.

F9 Madhuri Engineering 17.08.2022 D1

  1. 5
  2. 6
  3. 7
  4. 8

Answer (Detailed Solution Below)

Option 3 : 7

Nodal Analysis Question 14 Detailed Solution

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  • Loop: A closed path in a circuit where more than two meshes can occur is known as Loop i.e. there may be many meshes in a loop, but a mesh does not contain on one loop.
     
  • Mesh:
    • The number of independent loops for a network with n nodes and b branches is = b - n + 1
    • A mesh is a closed path in a circuit with no other paths inside it. In other words, a loop with no other loops inside it.
       
  • Node: A point or junction where two or more circuit elements (resistor, capacitor, inductor, etc.) meet is called Node. In other words, a point of connection between two or more branches is known as a Node.
     
  • Branch: That part or section of a circuit located between two junctions is called the branch. In a branch, one or more elements can be connected, and they have two terminals.

Application:

The given circuit diagram represent the node and branch in circuit,

F9 Madhuri Engineering 17.08.2022 D2

Total Branch = 1, 2, 3, 4 = 4 nos

Total Node = A, B, C = 3 nos

Hence,

Sum of branches and nodes = 7

In the circuit given below, all resistor values are in ohms. Find the voltage across 10 ohms resistor.

F1 S.B Deepak 03.03.2020 D 8

  1. 1 V
  2. 2.5 V
  3. 10 V
  4. 5.0 V

Answer (Detailed Solution Below)

Option 1 : 1 V

Nodal Analysis Question 15 Detailed Solution

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Concept:

Nodal Analysis:

  • Nodal Voltage Analysis uses the “Nodal” equations of Kirchhoff’s first law to find the voltage potentials around the circuit. So by adding together all these nodal voltages the net result will be equal to zero.

Let a network and find voltage V using nodal analysis

F2 U.B M.P 24.09.19 D 3

Applying nodal analysis at node V

\(\frac{{V - {V_1}}}{{{R_1}}} + \frac{{V - {V_2}}}{{{R_2}}} + \frac{{V - {V_3}}}{{{R_3}}} = 0\)

By solving it we can find voltage V

Calculation:

F1 Tapesh 30-9-2020 Swati D11

Apply Nodal at node A, we get:

\(\frac{{{V_A}}}{{40}} - 0.25 + \frac{{{V_A} - 5}}{{10}} = 0\)

\(\frac{{{V_A}}}{{40}} + \frac{{{V_A}}}{{10}} = 0.75\)

5VA = 0.75 × 40

VA = 6V

The voltage across 10 Ω is,

V10 Ω = VA – VB = 6 – 5 = 1V

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