Letter and Number Based MCQ Quiz - Objective Question with Answer for Letter and Number Based - Download Free PDF

The logic followed here is:

​Option 1) V21T

Option 2) N15L

Option 3) I8G

Option 4) E4C

Thus, out of all 'N15L' is the odd one out.

Hence, "Option 2" is the correct answer.

The logic followed here is:

Logic: First value - Third value = second value.

Option 1) T 7 M

⇒ T(20) - M(13) = 7.

Pattern follow.

Option 2) B 10 R

⇒ B(2) - R(18) = 10.

Pattern follow.

Option 3) U 13 H

⇒ U(21 - H(8) = 13.

Pattern follow.

Option 4) J 16 Z

⇒ J(10) - Z(26) = 11 ≠ 16.

Pattern doesn't follow.

Hence, the correct answer is "Option 4".

Logic followed here is:

Find the difference between the place values of the first and last letters and compare it with the given number.

Now check each option:

1. A25Z

⇒ Place value of A = 1, Place value of Z = 26

⇒ 26 - 1 = 25

2. R9I

⇒ Place value of R = 18, Place value of I = 9

⇒ 18 - 9 = 9

3. Q10G

⇒ Place value of Q = 17, Place value of G = 7

⇒ 17 - 7 = 10

4. D18U

⇒ Place value of D = 4, Place value of U = 21

⇒ 21 - 4 = 17, not 18

∴ The odd one is "Option 4" D18U.

The logic followed here is:

Only one number is perfect square.

Option 1) 115 → Not a perfect square.

Option 2) 196 → It is a perfect square(14² = 196)

Option 3) 135 → Not a perfect square.

Option 4) 164 → Not a perfect square.

So, Option 2) is odd one.

Hence, the correct answer is "Option 2".

The logic followed here is:

Logic: 1st number + 3rd number = (2nd number)².

For, (19, 6, 17)

⇒ (19 +17) = 6²

⇒ 36 = 36

For, (79, 11, 42)

⇒ (79 +42) = 112

⇒ 121 = 121

Similarly,

(14, 4, 2) 

⇒ (14 +2) = 42

⇒ 16 = 16.

Hence, the correct answer is "Option 4".

Logic: In the options the adding the number and place value of letter is 20.

1) P4 → 16 + 4 = 20

2) S2 → 19 + 2 = 21

3) O5 → 15 + 5 = 20

4) I11 → 09 + 11 = 20.

According to the positional values of the alphabets,

1) O14A → O = 15, A = 1 → 15 - 1 = 14

2) P14B → P = 16, B = 2 → 16 - 2 = 14

3) Z22D → Z = 26, D = 4 → 26 - 4 = 22

4) U20H → U = 21 , H = 8 → 21 - 8 = 13

Hence, the odd one among the given options is U20H.

According to the positional values of the letters as per the alphabetical series,

1) I4G → I - G = 9 - 7 = 2; (2)² = 4;

2) T16P → T - P = 20 - 16 = 4; (4)² = 16;

3) Y9V → Y - V = 25 - 22 = 3; (3)² = 9;

4) D25A → D - A = 4 - 1 = 3; (3)² = 9 ≠ 25

According to the positional values of the alphabets,

1) Z7 → Z = 26, 26 × 2 = 52; 5 + 2 = 7

2) N10 → N = 14, 14 × 2 = 28; 2 + 8 = 10

3) J2 → J = 10, 10 × 2 = 20; 2 + 0 = 2

4) U3 → U = 21 and 21 × 2 = 42; 4 + 2 = 6 ≠ 3

Hence, the odd one among the given options is U3.

Here the places of letters in English alphabet are multiplied and written in the middle of letters.

H160T → The value of H is 8 and value of T is 20 so the multiplication is 160.

E70N → The value of E is 5 and value of N is 14 so the multiplication is 70.

K198R → The value of K is 11 and the value of R is 18 so the multiplication is 198.

G109O → The value of G is 7 and the value of O is 15 so the multiplication is 105. 

According to the English alphabet series and its positional value:

The logic follows here is:

If we give number to each letter according to its alphabetical order we find that,

1) R + 3 + D = 18 + 3 + 4 = 25

2) Q + 5 + E = 17 + 5 + 5 = 27

3) P + 2 + G = 16 + 2 + 7 = 25

4) K + 4 + J = 11 + 4 + 10 = 25

Hence, "Q5E" is the correct answer.

If we write English alphabets from A - Z order and denote them with numbers from 1 to 26, then we have the following table:

So, the pattern followed here is,

W → 23^th letter → 2 + 3 = 5

J → 10^th letter → 1 + 0 = 1

Similarly,

M → 13^th letter → 1 + 3 = 4

V → 22^th letter → 2 + 2 = 4

→ M × V : 4 × 4

Hence, 4 × 4 is the correct answer.

According to the alphabetical positions of the letters

1) E - B = 5 - 2 = 3; 3 × 2 = 6;

2) R - H = 18 - 8 = 10; 10 × 2 = 20;

3) X - I = 24 - 9 = 15; 15 × 2 = 30 ≠ 32;

4) N - J = 14 - 10 = 4; 4 × 2 = 8

Hence, 'X32I' is the odd one out.

According to the positional values of the alphabets,

1) 1A9J → A = 1, J = 10 and not 9

2) 4D25Y → D = 4, Y = 25

3) 7G20T → G = 7, T = 20

4) 10J15O → J = 10, O = 15

Hence, the odd one among the given options is 1A9J.

(1) AGJ ⇒ A + 6 → G; G + 3 → J

(2) ILO ⇒ I + 3 → L; L + 3 → O

(3) EHK ⇒ E + 3 → H; H + 3 → K

(4) SVY ⇒ S + 3 → V; V + 3 → Y

Hence, AGJ is the odd one.