Block Diagram Reduction Technique MCQ Quiz in বাংলা - Objective Question with Answer for Block Diagram Reduction Technique - বিনামূল্যে ডাউনলোড করুন [PDF]

Last updated on Apr 10, 2025

পাওয়া Block Diagram Reduction Technique उत्तरे आणि तपशीलवार उपायांसह एकाधिक निवड प्रश्न (MCQ क्विझ). এই বিনামূল্যে ডাউনলোড করুন Block Diagram Reduction Technique MCQ কুইজ পিডিএফ এবং আপনার আসন্ন পরীক্ষার জন্য প্রস্তুত করুন যেমন ব্যাঙ্কিং, এসএসসি, রেলওয়ে, ইউপিএসসি, রাজ্য পিএসসি।

Latest Block Diagram Reduction Technique MCQ Objective Questions

Top Block Diagram Reduction Technique MCQ Objective Questions

Block Diagram Reduction Technique Question 1:

F1 U.B 19.5.20 Pallavi D 5

  1. C(s)R(s)=G1G2
  2. C(s)R(s)=1+G1+G1G2
  3. C(s)R(s)=1+G2+G1G2
  4. C(s)R(s)=G1+G2

Answer (Detailed Solution Below)

Option 3 : C(s)R(s)=1+G2+G1G2

Block Diagram Reduction Technique Question 1 Detailed Solution

The given block diagram can be reduced as shown below.

F1 U.B 19.5.20 Pallavi D 6

F1 U.B 19.5.20 Pallavi D 7

C(s)R(s)=(1+G1)G2+1=1+G2+G1G2

Block Diagram Reduction Technique Question 2:

For the control system shown below, the transfer function C(s)R(s) is

F1 U.B Madhu 04.05.20 D4

  1. G2G3(G1+G4)1G1G2G3H1
  2. G2G3(G1+G4)1G2G3H1(G1+G4)
  3. G2G3(G1+G4)1+G1G2G3H1
  4. G2G3(G1+G4)1+G2G3H1(G1+G4)

Answer (Detailed Solution Below)

Option 3 : G2G3(G1+G4)1+G1G2G3H1

Block Diagram Reduction Technique Question 2 Detailed Solution

At D(s) = 0, the block diagram can be redrawn as shown below.

F1 U.B Madhu 04.05.20 D5

By applying Mason’s gain formula

Forward paths = G1G2G3, G4G2G3

Here, we are having only one loop (G4 is connected to input R(s). So, it cannot form a loop)

Loops = -G1G2G3 H1

Δ = 1 + G1G2G3 H1

Δ1 = 1, Δ2 = 1

Transfer function =C(s)R(s)=G1G2G3+G2G3G41+G1G2G3H1

=G2G3(G1+G4)1+G1G2G3H1

Block Diagram Reduction Technique Question 3:

Figure shows the block diagram of an amplifier system with an overall feedback loop and additive noise ‘N’ to the amplifier A2

20.12.2018.001.00406

To reduce the effect to noise

  1. A2 gain should be increased
  2. The feedback factor β should be increased
  3. The gain A1 should be increased
  4. Both A1 and A2 gain should be increased 

Answer (Detailed Solution Below)

Option 3 : The gain A1 should be increased

Block Diagram Reduction Technique Question 3 Detailed Solution

Assume N = 0

The Transfer function

20.12.2018.001.00407

VoVi=A1A21+βA1A2         ........(1)

Assume

20.12.2018.001.00408

V0N=A21+βA1A2           .......(2)

V0N=A21+βA1.A2=0

V0N=11A2+βA1=0

Now, to reduce the effect of noise:

1/A2 + βA1 should tend to ∞.

For this to happen, either:

1) A2 should tend to zero, or

2) β 'or' A1 should tend to infinity.

But since increasing β to infinity will reduce the effect of Vi from 1st Transfer function.

So, It is desirable to increase A1.

Of the given Options only 3rd is satisfying this requirement.

Block Diagram Reduction Technique Question 4:

For the feedback system shown in the given figure, the forward path does not affect the system output when KG is

Control Systems 2 Komal images Q18

  1. Small
  2. Negative
  3. One
  4. Very large

Answer (Detailed Solution Below)

Option 4 : Very large

Block Diagram Reduction Technique Question 4 Detailed Solution

CR=KG1+KGH

Here, If KGH > > 1,

1 + KGH ≈ KGH

CR=KGKGH=1H

Hence if kG is very large, the transfer function is independent of the forward path.

Block Diagram Reduction Technique Question 5:

Which one of the following block diagrams in options given is equivalent to the below-shown block diagram?

  1. mdusee6
  2. mdusee7
  3. mdusee8
  4. None of the above

Answer (Detailed Solution Below)

Option 4 : None of the above

Block Diagram Reduction Technique Question 5 Detailed Solution

The transfer function given is

CR=1H×GH1GH=G1GH

Hence option (c) is wrong

Considering option (b), CR=H×G1G=GH1GH

Considering option (a), CR=H1GH

None of the options are correct.

Block Diagram Reduction Technique Question 6:

In the below figure, output C1 due to R1 and R2 is given by:

F1 Engineering Mrunal 13.03.2023 D17

  1. G1R1G1G3G4R21G1G2G3G4
  2. G1R1G2G3G4R21G1G2G3G4
  3. G1R1G1G3G2R21G1G2G3G4
  4. G1R1G1G2G3G4R21G1G2G3G4

Answer (Detailed Solution Below)

Option 1 : G1R1G1G3G4R21G1G2G3G4

Block Diagram Reduction Technique Question 6 Detailed Solution

Concept:

According to Mason’s gain formula, the transfer function is given by

TF=k=1nMkΔkΔ

Where, n = no of forward paths

Mk = kth forward path gain

Δk = 1 - Sum of the loop that exists after removal of the kth forward path + sum of the gain product of two non-touching loops

Δ = 1 – (sum of the loop gains) + (sum of the gain product of two non-touching loops) – (sum of the gain product of three non-touching loops)

Calculation

While calculating output C1 due to R1 and R2 , keep C2 = 0

The forward path from R1 to C1 is:

M1=G1R1

The forward path from R2 to C1 is:

M2=G1G3G4R2

Self-loop gain:

Δ=1G1G2G3G4

T(s)=G1R1G1G3G4R21G1G2G3G4

Hence, the correct answer is option 1.

Block Diagram Reduction Technique Question 7:

The transfer function CR2 in the block diagram shown below is given by

F1 U.B 10.9.20 Pallavi D12

  1. G2+G1G31+G3H1+G2
  2. G31+G3H1
  3. (G1+G2)G31+(G1+G2)G3H1
  4. (G1+G2)G31+G3H1

Answer (Detailed Solution Below)

Option 2 : G31+G3H1

Block Diagram Reduction Technique Question 7 Detailed Solution

Concept:

According to Mason’s gain formula, the transfer function is given by

TF=k=1nMkΔkΔ

Where, n = no of forward paths

Mk = kth forward path gain

Δk = the value of Δ which is not touching the kth forward path

Δ = 1 – (sum of the loop gains) + (sum of the gain product of two non-touching loops) – (sum of the gain product of three non-touching loops).

Calculation:

Forward path: G3

Loop: -G3 H1

The transfer function is,

CR1=G31+G3H1

Block Diagram Reduction Technique Question 8:

Determine the closed loop transfer function C(s) / R(s) for the block diagram shown in Fig.

F15 Jai Prakash 18-2-2021 Swati D11

  1. C(s)R(s)=G11G1H1G1H1H2
  2. C(s)R(s)=G11+G1H1+G1H2
  3. C(s)R(s)=G11G1H1+G1H2
  4. C(s)R(s)=G11+G1H1+G1H1H2
  5. None of these

Answer (Detailed Solution Below)

Option 3 : C(s)R(s)=G11G1H1+G1H2

Block Diagram Reduction Technique Question 8 Detailed Solution

Concept:

F1 U.B Deepak 26.03.2020 D4

If the open-loop transfer function G(s) is connected in positive feedback with a feedback gain of H(s), then the transfer function of the closed-loop system is: G(s)1G(s)H(s)

If the open-loop transfer function G(s) is connected in negative feedback with a feedback gain of H(s), then the transfer function of the closed-loop system is: G(s)1+G(s)H(s)

When two systems are connected in parallel, then the overall gain of the system will be the sum of their individual gains.

When two systems are connected in cascade connection, then the overall gain of the system will be the product of their individual gains.

Calculation:

G1 and H1 are connected in positive feedback.

The equivalent for this combination is =G11G1H1

Now, this block and H2 are in negative feedback.

The equivalent transfer function is,

C(s)R(s)=G11G1H11+G1H21G1H1

=G11G1H1+G1H2

Block Diagram Reduction Technique Question 9:

Transfer function C(s)R(s) of the system shown in the figure here is:

F1 Uday.B 14-12-20 Savita D15

  1. GaGbHa(1+GaGbHb)
  2. GaGb1+GaGbHaHb
  3. GaGbHbHa(1+GaGbHb)
  4. GaHbHa(1+GaGbHb)

Answer (Detailed Solution Below)

Option 4 : GaHbHa(1+GaGbHb)

Block Diagram Reduction Technique Question 9 Detailed Solution

Concept:

F1 U.B Deepak 26.03.2020 D4

If the open-loop transfer function G(s) is connected in positive feedback with a feedback gain of H(s), then the transfer function of the closed-loop system is: G(s)1G(s)H(s)

If the open-loop transfer function G(s) is connected in negative feedback with a feedback gain of H(s), then the transfer function of the closed-loop system is: G(s)1+G(s)H(s)

When two systems are connected in parallel, then the overall gain of the system will be the sum of their individual gains.

When two systems are connected in cascade connection, then the overall gain of the system will be the product of their individual gains.

Calculation:

The transfer function of the right part of the given block diagram is GaGb1+GaGbHb

Both are connected in cascade connection, therefore the overall transfer function is

=GaHbHa(1+GaGbHb)

Block Diagram Reduction Technique Question 10:

Consider the following three cases of block diagram algebra A, B and C.

A.

GATE EC FT10 Controls images Q1

B.

GATE EC FT10 Controls images Q1a

C.

GATE EC FT10 Controls images Q1c

Which of the above relations are correct?

  1. A and B
  2. B and C
  3. A and C
  4. A, B and C
  5. B only

Answer (Detailed Solution Below)

Option 2 : B and C

Block Diagram Reduction Technique Question 10 Detailed Solution

From block diagram B

First Case: Z = XG – Y

Second Case: Z = (X – Y/G)G = XG – Y

From block diagram C

First Case: Z = (X – Y)G

Second Case: Z = (XG- YG) = (X – Y)G

From block diagram A,

First Case: Z = (XG1 – Y)G2 = XG1G2 – YG2

Second Case: Z = (XG2 – Y)G1 = XG1G2 – YG1

Hence, B and C are correct.
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