When the depth of immersion of a plane surface is increased the centre of pressure will

Concept:
We know that the centre of pressure is the point at which resultant pressure force due to fluid acts and it is given by-

\({\rm{h}} = {\rm{\bar x}} + \frac{{{{\rm{I}}_{\rm{G}}}}}{{{\rm{A\bar x}}}}{\left( {\sin {\rm{\theta }}} \right)^2}\)

Where, h represents the centre of pressure, IG = second moment of area, A = area, and x̅ = centre of gravity.

Now, as the depth of immersion increases, x̅ increases which results into increase in h but the rate of increment would be decreased because the factor \(\frac{{{{\rm{I}}_{\rm{G}}}}}{{{\rm{A\bar x}}}}{\left( {\sin {\rm{\theta }}} \right)^2}\) has x̅ in the denominator.

Hence h will come closer to x̅.

Important Points

For θ = 90°, means vertical, the centre of pressure is farthest to the centre of gravity.

For θ = 0°, means horizontal, the centre of pressure is coinciding with the centre of gravity.