Question
Download Solution PDFWhat will be the maximum sag if working tension is 4000 kg, resultant force per meter length of conductor is 2 and span length is 320 meter?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFThe correct answer is option 2): 6.4
Concept:
Maximum Sag (S) =Wl2 / 8T
Where
W = weight of conductor per meter length in Kg per meter
l = Span length in meter
T = Working tension in Kg
Calculation:
Resultant force per meter length of conductor = Weight of conductor per meter length
W = 2 kg/m,
T = 4000 kg,
l = 320 meters,
\(S = \frac{{2 \times {{320}^2}}}{{8 \times 4000}} = 6.4\)
Last updated on Jun 10, 2024
-> The UPMRC JE Result has been announced for the written exam held on 11th, 12th and 14th May 2024.
-> UPMRC JE Notification was released for a total of 132 vacancies of Junior Engineer (Electrical) & S&T were released.
-> The selection process includes a Written Test (CBT), Interview, Medical Examination, and Document Verification.
-> Candidates with an engineering diploma are eligible for this exam.
-> The candidates must prepare well for the UPMRC JE exam by practicing the previous year's papers.