What is the total capacitance in the given circuit?

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Answer 1

Concept:

When capacitors are connected in parallel, the total capacitance is the sum of the individual capacitors' capacitances.

$C_{e q} (p a r a l l e l) = C_{1} + C_{2} + C_{3} + \dots + C_{4}$

When capacitors are connected in series, the total capacitance is less than the least capacitance connected in series.

$\frac{1}{C_{e q} (s e r i e s)} = \frac{1}{C_{1}} + \frac{1}{C_{2}} + \dots + \frac{1}{C_{n}}$

Calculation:

For the two 6 F capacitors connected in parallel, the resultant capacitance will be:

C_net = 6 + 6 = 12 F

Also, the two 2F capacitors connected in series connection will be equivalent to a single capacitor of value:

C_net = 2/2 = 1 F

The resultant circuit is drawn as:

F2 Shubham Bhatt 3.3.21 Pallavi D8

Since the 1 F and 12 F capacitors are connected in parallel, the net capacitance will be:

C_net = 1 + 12 = 13 F

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