Question
Download Solution PDFWhat is the magnetic flux density at distance r due to a long conductor carrying current of I?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFCONCEPT:
The magnetic field at point P due to a straight conductor is given by:
B = \(μ_0 I \over{2\pi d}\)
where B is the magnetic field at point P, μ0 permeability of the medium I is the current in the in the wire and d is the distance from the wire to that point.
EXPLANATION:
At distance r from an infinitely long straight current carrying conductor, magnetic field is:
B = \(μ_0 I \over{2\pi r}\)
where B is the magnetic field, μ0 permeability of the medium I is the current in the wire, and r is the distance from the wire to that point.
So B α 1/r
Important Points
Magnetic flux density of coil is given by \(B = \;\frac{{{\mu _o}NI}}{{2R}}\) T
Magnetic flux density of solenoid is given by \(B = \;\frac{{{\mu _0}\;NI}}{l}\) T
Magnetic flux density of long straight wire \(B = \;\frac{{{\mu _0}I}}{{2\pi r}}\) T
Last updated on May 29, 2025
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