Three identical impedances are connected in delta. The load is supplied by a 3-phase supply of 300 V. The line current is \(\rm 30\sqrt3\,A\). Calculate the impedance per phase.

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SSC JE Electrical 07 Jun 2024 Shift 3 Official Paper - 1
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  1. 30 Ω 
  2. 10 Ω
  3. \(10\sqrt3\) Ω
  4. 20 Ω

Answer (Detailed Solution Below)

Option 2 : 10 Ω
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Detailed Solution

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Concept

For delta connected system:

VL = VP 

\(I_p={I_L\over \sqrt {3}}\)

For star-connected system:

\(V_p={V_L\over \sqrt {3}}\)

IL = IP

where, VL and IL are line voltage and line current respectively

VP and IP are phase voltage and phase current respectively

Calculation

Given, V= VP = 300 V

IL = \(\rm 30\sqrt3\,A\)

\(I_p={30\sqrt{3}\over \sqrt {3}}=30A\)

\({R}={300\over 30}=10\Omega\)

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