The volume of a cone with height equal to radius, and slant height 5 cm is : 

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SSC CGL 2023 Tier-I Official Paper (Held On: 17 Jul 2023 Shift 1)
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  1. \( \frac{125 \pi}{12 \sqrt{3}} \mathrm{~cm}^3 \)
  2. \( \frac{125 \pi}{6 \sqrt{3}} \mathrm{~cm}^3 \)
  3. \( \frac{125 \pi}{12 \sqrt{2}} \mathrm{~cm}^3 \)
  4. \( \frac{125 \pi}{6 \sqrt{2}} \mathrm{~cm}^3\)

Answer (Detailed Solution Below)

Option 4 : \( \frac{125 \pi}{6 \sqrt{2}} \mathrm{~cm}^3\)
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Detailed Solution

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Given:

The radius and height of the cone are same.

Slant height = 5 cm

Formula used:  

Volume of cone = (1/3) π r2 h

Slant height = √(h2 + r2

Where,

r = Radius of the cone

h = Height of the cone

l = slant height

Calculation

let the radius and height of the cone be x.

5 = √(x2 + x2

x = 5/√2

Volume of cone = (1/3) π r2 h

⇒ (1/3) × π × (5/√2)2 × 5/√2

⇒ (1/3) × π × (25/2) × 5/√2

⇒ 125π /6√2 cm3

The volume of a cone is 125π/6√2 cm3

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