Question
Download Solution PDFThe value of Iz shown in the given circuit is ________.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept
The value of Zener current is given by:
\(I_Z=I_S-I_L\)
\(I_Z={V_S-V_Z\over R_S}-{V_Z\over R_L}\)
where, Iz = Zener current
Vz = Zener voltage
Vs = Source voltage
Rs = Source resistance
RL = Load resistance
Calculation
Given, Vz = 20 V
Vs = 30 V
Rs = 100 Ω = 0.1 kΩ
RL = 1 kΩ
\(I_Z={30-20\over 0.1}-{20\over 1}\)
IZ = 100 - 20 mA = 0.08 A
Last updated on May 29, 2025
-> SSC JE Electrical 2025 Notification will be released on June 30 for the post of Junior Engineer Electrical/ Electrical & Mechanical.
-> Applicants can fill out the SSC JE application form 2025 for Electrical Engineering from June 30 to July 21.
-> SSC JE EE 2025 paper 1 exam will be conducted from October 27 to 31.
-> Candidates with a degree/diploma in engineering are eligible for this post.
-> The selection process includes Paper I and Paper II online exams, followed by document verification.
-> Prepare for the exam using SSC JE EE Previous Year Papers.