The total number of lone pairs of electrons in $XeO_{4}$ is

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UP LT Grade Teacher (Science) 2018 Official Paper

Answer 1

CONCEPT:

Determination of Lone Pairs in XeO₄

Xenon (Xe) belongs to group 18 (noble gases) and has 8 valence electrons.
In XeO₄, xenon forms bonds with 4 oxygen atoms through double bonds.
Each oxygen atom contributes 2 electrons to form a double bond with xenon.
Since all 8 valence electrons of xenon are involved in bonding, there are no lone pairs remaining on the xenon atom.

EXPLANATION:

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The molecular structure of XeO₄ involves xenon in the center with 4 oxygen atoms forming double bonds around it.
Each double bond consists of 4 electrons (2 from xenon and 2 from oxygen).
Thus, the total number of electrons used for bonding is 8, which is equal to the valence electrons of xenon.
Since all electrons are utilized in bonding, xenon has no lone pairs of electrons in XeO₄.

Therefore, the total number of lone pairs of electrons in XeO₄ is zero.