Question
Download Solution PDFThe standard deviation of the first 10 natural numbers is 3.028. What will be the standard deviation of the first 20 natural numbers?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFFormula: \(σ = \sqrt {{(n^2 - 1)}\over 12}\); where, σ = standard deviation, n = sample size
Or, σ = \(\sqrt{(20^2 - 1) \over 12} = 5.766 \approx 5.8\)
This is closest to 5.845
Hence, the standard deviation of the first 20 natural numbers is 5.845.
Last updated on Jul 16, 2025
-> This year, the Staff Selection Commission (SSC) has announced approximately 14,582 vacancies for various Group B and C posts across government departments.
-> The SSC CGL Tier 1 exam is scheduled to take place from 13th to 30th August 2025.
-> Aspirants should visit ssc.gov.in 2025 regularly for updates and ensure timely submission of the CGL exam form.
-> Candidates can refer to the CGL syllabus for a better understanding of the exam structure and pattern.
-> The CGL Eligibility is a bachelor’s degree in any discipline.
-> Candidates selected through the SSC CGL exam will receive an attractive salary. Learn more about the SSC CGL Salary Structure.
-> Attempt SSC CGL Free English Mock Test and SSC CGL Current Affairs Mock Test.
-> The Bihar Sakshamta Pariksha Admit Card 2025 for 3rd phase is out on its official website.