The ripple counter shown in the following figure uses flip flops that trigger on the negative‐edge transition of the C‐P input. Is the counter self‐starting?

Question

Question

This question was previously asked in

UGC NET Paper 2: Electronic Science 3rd Dec 2021 Shift 2

Answer 1

The starting of the counter will be decided by that counter which is receiving the clock pulse.

qImage14820

Flip-flop 1 is receiving the clock pulse. The characteristic equation is:

\(Q_{n+1}=J\overline{Q_n}+\overline{K}Q_n\)

J and K both are connected to \(\overline{Q_n}\)

\(Q_{n+1}=\overline{Q_n}\space \overline{Q_n}+\overline{\overline {Q_n}}Q_n\)

\(Q_{n+1}=\overline{Q_n}+Q_n\)

\(Q_{n+1}=1\)

The counter will self-start.

The correct answer is option 1.