The molality (in mol kg-1) of 1 mole of solute in 50 g of solvent is

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  1. 10
  2. 20
  3. 30
  4. 40

Answer (Detailed Solution Below)

Option 2 : 20
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CONCEPT:

Molality (m)

  • Molality (m) is a measure of the concentration of a solute in a solution.
  • It is defined as the number of moles of solute per kilogram of solvent.
  • The formula for molality is:

    m = (moles of solute) / (mass of solvent in kg)

EXPLANATION:

  • Given data:
    • Moles of solute = 1 mole
    • Mass of solvent = 50 g
  • Convert mass of solvent to kilograms:
    • 50 g = 50 / 1000 kg = 0.05 kg
  • Using the molality formula:
    • m = (moles of solute) / (mass of solvent in kg)
    • = 1 mole / 0.05 kg
    • = 20 mol kg-1

Therefore, the molality of 1 mole of solute in 50 g of solvent is 20 mol kg-1.

Other Options Explanation:

  • Option 1 (10 mol kg-1):
    • This would be the result if the mass of the solvent was 100 g (0.1 kg) instead of 50 g.
    • m = 1 mole / 0.1 kg = 10 mol kg-1
  • Option 3 (30 mol kg-1):
    • This would be the result if the mass of the solvent was approximately 33.33 g (0.03333 kg).
    • m = 1 mole / 0.03333 kg ≈ 30 mol kg-1
  • Option 4 (40 mol kg-1):
    • This would be the result if the mass of the solvent was 25 g (0.025 kg).
    • m = 1 mole / 0.025 kg = 40 mol kg-1
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