Question
Download Solution PDFThe minimum number of links in a constrained planer mechanism involving revolute pairs and two higher pairs is
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
For a simple mechanism, the degree of freedom (F) is given by the Grubler’s criterion:
F = 3 (n - 1) - 2j - h
Where j = number of revolute joints
n = number of links
h = number of higher pairs
For a constrained planar mechanism, DOF is 1
⇒ 1 = 3 (n - 1) - 2j - 2
⇒ 3n - 2j = 6
⇒ 2j = 3n - 6
The RHS of the equation should be positive and even number,
Put n = 3
2j = 3 × 3 - 6 = 3 odd
put n = 4
2j = 3 × 4 - 6 = 6 even
So, the minimum value of n should be 4
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