The Fourier Transform of an real and even function results in:

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  1. a purely real and odd function
  2. a purely imaginary and even function
  3. an imaginary and odd function
  4. a purely real and even function

Answer (Detailed Solution Below)

Option 4 : a purely real and even function
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Concept: Fourier Transform Symmetry Property

If a time-domain function is:

  • Real: It has no imaginary part

  • Even: f(t) = f(-t)

Then it's  Fourier Transform will be:

  • Purely real

  • Even: F(ω)=F(ω)

🔍 Example: Cosine Wave

Let’s take: f(t) = cos(ω0t)

  • It is real.

  • It is even, because

Fourier Transform of is: F(ω)=π [δ(ωω0)+δ(ω+ω0)]

This result is:

  • Purely real (involves delta functions, no imaginary component)

  • Even since it's symmetric around

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