Question
Download Solution PDFThe following sequence of instructions is executed by an 8085 microprocessor :
1000 H | LXI SP, 27FF H |
1003 H | CALL 1006 H |
1006 H | POP H |
The contents of the stack pointer (SP) and the HL register pair on completion of execution of these instructions are
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFThe correct option is a.
Detailed solution:
Step-by-step, let's examine the instructions to observe how the stack pointer (SP) and HL register pair are impacted.
LXI SP, 27FFH: The stack pointer (SP) should be loaded with the instantaneous value 27FFH.
At first, SP equals 27FFH.
CALL 1006H: Use the memory address 1006H to call a procedure.
The following instruction (1003H) will have its address pushed onto the stack.
SP will decrease by two.
POP H: Insert the topmost stack node into the pair of HL registers.
The low-order register L is filled with the value that is now 27FDH at the memory location that SP pointed to.
The high-order register H is filled with the value that was loaded at the memory location that SP+1 pointed to (27FEH).
The SP will rise by two.
Following these instructions, the following values will be present in the HL register pair and the stack pointer (SP):
The initial value prior to the sequence is 27FFH.
(Value popped off the stack) HL = 1003H
Thus, what follows will be:
SP = 27FFH, HL = 1003H
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