The critical radius of insulation for asbestors with k = 0.125 W/mK surrounding a pipe exposed to room air with h = 2.5 W/m2K is

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HPCL Engineer Mechanical 12 Aug 2021 Official Paper (Shift 1)
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  1. 20 mm
  2. 312.5 mm
  3. 50 mm
  4. 5 mm

Answer (Detailed Solution Below)

Option 3 : 50 mm
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Concept:

Critical radius:

The insulation radius at which resistance to heat flow is minimum and consequently heat flow rate is maximum is called “critical radius”.

The critical radius of insulation for a cylindrical body:

\({r_{cr,cylinder}} = \frac{k_{ins}}{h}\)

The critical radius of insulation for a spherical shell:

\({r_{cr,sphere}} = \frac{{2k_{ins}}}{h}\)

Critical thickness:

The thickness up to which heat flow increases and after which heat flow decreases is termed as Critical thickness.

(rcr)thickness = rcr - r

Calculation:

Given:

k = 0.125 W/mK, h = 2.5 W/m2K

The critical radius of insulation for a cylindrical body:

\({r_{cr,cylinder}} = \frac{k_{ins}}{h}\)

\({r_{cr,cylinder}} = \frac{0.125}{2.5}=0.05\;m=50\;mm\)

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