The coordinates of the point that divides the line segment joining the points (- 5, 5) and (7, -3) internally in the ratio 3 ∶ 1 are given by

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RRB ALP CBT I 29 Aug 2018 Shift 1 Official Paper
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  1. (-2, 3)
  2. (4, -1)
  3. \(\left(\frac{5}{2},0\right)\)
  4. (1, 1)

Answer (Detailed Solution Below)

Option 2 : (4, -1)
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Detailed Solution

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Given:

The line joining the points (–5, 5) and (7, –3) internally in the ratio 3 : 1

Concept used:

(x, y) = [{m1 × x2 + m2 × x1}/m1 + m2], [{m1 × y2 + m2 × y1}/m1 + 2]

Calculation:

Let P(x, y) be the point that divides the line segment internally. 

Here, m1 = 3, m2 = 1

(x1, y1) = (-5, 5) and (x2, y2) = (7, -3)

Putting the above values in the above formula, we get

⇒ x = [{3(7) + 1(-5)}/4], y = [{3(-3) + 1(5)}/4]

⇒ x = 16/4, y = -4/4

x = 4, y = -1

∴ (4, -1) is the point that divides the line segment 

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