Question
Download Solution PDFThe conditions required for maximum discharge through a triangular channel having a depth of flow y are:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Most efficient channel: A channel is said to be efficient if it carries the maximum discharge for the given cross-section which is achieved when the wetted perimeter is kept a minimum.
a) For a triangular channel,
The channel with a side slope of 1:1 is the most efficient channel.
Area of triangle A = 1/2 × y × 2 y
Wetted Perimeter P = 2 √2y
The hydraulic radius for the given section is the ratio of the cross-sectional area to the wetted perimeter of the section.
\({\rm{R}} = {\rm{}}\frac{{\rm{A}}}{{\rm{P}}} = \frac{{{{\rm{y}}^2}}}{{2√ 2 {\rm{y}}}} = \frac{{\rm{y}}}{{2√ 2 }}\)
Last updated on May 28, 2025
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