The base of a right pyramid is an equilateral triangle with side 8 cm, and its height is 30 \(\sqrt{3}\) cm. The volume (in cm3)

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SSC CGL Tier 2 Quant Previous Paper 2 (Held On: 16 November 2020)
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  1. 240\(\sqrt{3}\) cm3
  2. 360\(\sqrt{3}\) cm3
  3. 480 cm3
  4. 360 cm3

Answer (Detailed Solution Below)

Option 3 : 480 cm3
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Detailed Solution

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Given:

Side of equilateral triangle = 8 cm

Height = 30 \(√{3}\) cm

Formula used:

The volume of the pyramid (V) = (1/3) × Base Area × Height

Area of equilateral triangle = (√3/4) × a2   (where a is the side of the equilateral triangle)

Calculations:

⇒ Area of triangle = (√3/4) × 8 × 8

⇒ Area of equilateral triangle = 16√3 cm2

⇒ The volume of pyramid = (1/3) × 16√3 × 30√3

⇒ V = 480 cm3

∴ The volume of the pyramid is 480 cm3

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