క్రింది పటంలో, B మరియు D కేంద్రాలుగా గల వృత్తాల వ్యాసార్థాలు వరుసగా 4 సెం.మీ మరియు x సెం.మీ. AC రెండు వృత్తాలకు స్పర్శరేఖ. x విలువను కనుగొనండి.

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SSC CGL 2023 Tier-I Official Paper (Held On: 25 Jul 2023 Shift 4)
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  1. 6
  2. 3
  3. 7
  4. 5

Answer (Detailed Solution Below)

Option 1 : 6
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PYST 1: SSC CGL - General Awareness (Held On : 20 April 2022 Shift 2)
25 Qs. 50 Marks 10 Mins

Detailed Solution

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ఇవ్వబడింది:

చిన్న వృత్తం యొక్క వ్యాసార్థం (r) = 4 సెం.మీ

AE = 6 సెం.మీ; EC = 9 సెం.మీ

ఉపయోగించిన భావన:

స్పర్శబిందువు వద్ద వృత్తం యొక్క వ్యాసార్థంతో స్పర్శరేఖ లంబకోణం చేస్తుంది.

శీర్షాభిముఖ కోణాలు సమానం.

గణన:

AD ⊥ AC మరియు BC ⊥ AC

∠DAE = ∠BCE = 90°

△DAE మరియు △BCE లలో

∠DAE = ∠BCE = 90°

∠AED = ∠BEC (శీర్షాభిముఖ కోణం)

△DAE ~ △BCE (AA సరూపత ద్వారా)

C.P.C.T ద్వారా

AE/EC = AD/BC

⇒ 6/9 = 4/BC

⇒ BC = 36/6 = 6 సెం.మీ

∴ సరైన సమాధానం 6 సెం.మీ.

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