Sum of the infinite series 49 + 0.3 × 490.3 × 0.3 × 49 0.3 × 0.3 × 0.3 × 49 +...

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UP TGT Mathematics 2019 Official Paper
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  1. 89
  2. 98
  3. 8989
  4. 70

Answer (Detailed Solution Below)

Option 4 : 70
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Detailed Solution

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Formula Used:

Sum of the infinite series = \(\frac{a}{(1 - r)}\)

r = a2/a1

a = First term of the series

r = Common ratio

Calculation: 

49 + 0.3 × 49 + 0.3 × 0.3 × 49 0.3 × 0.3 × 0.3 × 49 +...

⇒ 49 (1 + 0.3  + 0.3 × 0.3 0.3 × 0.3 × 0.3 +...)  

⇒ 49 (1 + {0.3  + 0.3 × 0.3 0.3 × 0.3 × 0.3 +...})   

⇒ 49 (1 + \(\frac{0.3}{(1 - 0.3)}\)) 

⇒ 49 (1 + \(\frac{0.3}{0.7}\))

⇒ 49 (\(\frac{0.7 + 0.3}{0.7}\))

⇒ 49 × \(\frac{1}{0.7}\)

⇒ 70

∴ 49 + 0.3 × 49 + 0.3 × 0.3 × 49 0.3 × 0.3 × 0.3 × 49 +... = 70

The correct option is 4 i.e. 70
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