One Pascal (Pa) equals which of the following?

This question was previously asked in
RRB JE CBT I - (Held On: 1 June 2019 Shift 3)
View all RRB JE Papers >
  1. Newton metre squared N m2
  2. Newton per metre squared N/m2
  3. Newton metre N m
  4. Newton per metre N/m

Answer (Detailed Solution Below)

Option 2 : Newton per metre squared N/m2
Free
General Science for All Railway Exams Mock Test
2.1 Lakh Users
20 Questions 20 Marks 15 Mins

Detailed Solution

Download Solution PDF
The correct answer is Newton per metre squared N/m²

Key Points

  • One Pascal (Pa) is defined as one Newton of force applied over an area of one square meter.
  • It is a derived unit of pressure used in the International System of Units (SI).
  • The formula for pressure (P) is given by P = F/A, where F is the force applied perpendicular to the surface (in Newtons) and A is the area over which the force is distributed (in square meters).
  • Thus, 1 Pa = 1 N/m².

Additional Information

  • The Pascal is named after Blaise Pascal, a French mathematician, physicist, and inventor.
  • It is commonly used to measure internal pressure, stress, Young's modulus, and tensile strength.
  • Other units of pressure include the bar, atmosphere (atm), and torr, but the Pascal is the standard SI unit.
  • 1 bar = 100,000 Pa, 1 atm ≈ 101,325 Pa, and 1 torr ≈ 133.322 Pa.
Latest RRB JE Updates

Last updated on Jun 16, 2025

-> RRB JE CBT 2 answer key 2025 for June 4 exam has been released at the official website.

-> Check Your Marks via RRB JE CBT 2 Rank Calculator 2025

-> RRB JE CBT 2 admit card 2025 has been released. 

-> RRB JE CBT 2 city intimation slip 2025 for June 4 exam has been released at the official website.

-> RRB JE CBT 2 Cancelled Shift Exam 2025 will be conducted on June 4, 2025 in offline mode. 

-> RRB JE CBT 2 Exam Analysis 2025 is Out, Candidates analysis their exam according to Shift 1 and 2 Questions and Answers.

-> The RRB JE Notification 2024 was released for 7951 vacancies for various posts of Junior Engineer, Depot Material Superintendent, Chemical & Metallurgical Assistant, Chemical Supervisor (Research) and Metallurgical Supervisor (Research). 

-> The selection process includes CBT 1, CBT 2, and Document Verification & Medical Test.

-> The candidates who will be selected will get an approximate salary range between Rs. 13,500 to Rs. 38,425.

-> Attempt RRB JE Free Current Affairs Mock Test here

-> Enhance your preparation with the RRB JE Previous Year Papers

Get Free Access Now
Hot Links: teen patti all game real cash teen patti teen patti plus happy teen patti teen patti cash