In the moment distribution method, the sum of distribution factors for all the members meeting at a joint is always:

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HPCL Engineer (Civil) 04 Nov 2022 Official Paper
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  1. greater than one
  2. equal to one
  3. lesser than one
  4. equal to zero 

Answer (Detailed Solution Below)

Option 2 : equal to one
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Detailed Solution

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Concept:

Distribution factor (DF):

\(DF={Stiffness\, of\, a\, member\over Sum\, of\, stiffness\, of \, all\, members\, at\, that \, joint}\)

Or

\(DF={Relative\, stiffness\, of\, a\, member\over sum\, of\, relative\, stiffness\, of \, all\, members\, at\, that \, joint}\)

 

F1 Engineering Mrunal 20.02.2023 D14 F1 Engineering Mrunal 20.02.2023 D15

Where M1, M2, M3, and M4 are moment induced in member OA, OB, OC, and OD respectively.

The summation of DF for all members at a joint is one.

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