Question
Download Solution PDFIn the compression stroke of an IC engine the heat rejected to the cooling water is 65 kJ/kg and the work input is 108 kJ/kg. The change in specific internal energy of the working fluid would be:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
The first law of thermodynamics states that the change in internal energy of a system is given by:
\( Δ U = Q - W \)
Where:
- ΔU = Change in internal energy (kJ/kg)
- Q = Heat added to the system (kJ/kg)
- W = Work done by the system (kJ/kg)
Given:
Heat rejected to cooling water, Q = -65 kJ/kg
Work input, W = 108 kJ/kg
Calculation:
Applying the first law of thermodynamics:
\( Δ U = Q - W \)
\( Δ U = (-65) + (108) \)
\( Δ U = 43\) kJ/Kg
Since Δ U is positive, it indicates a gain in internal energy.
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