Question
Download Solution PDFIn the analysis of unseeded domestic waste water BOD test, the data used is 6ml of waste in a 300 ml bottle, initial DO of 8 mg/l and 5 day DO is 4 mg/l. Compute 5day BOD of waste water.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Biochemical Oxygen demand (BOD):
It is the total amount of oxygen required to oxidize the biodegradable organic matter present in wastewater through microbial utilization of organics.
BOD = (Initial Dissolve Oxygen - Final Dissolve Oxygen) × Dilution Factor
where
Dilution Factor = \(\rm\frac{{Volume\;of\;diluted\;sample}}{{Volume\;of\;undiluted\;sample}}\)
Calculation:
Given:
DOInitial = 8 mg/L
DOFinal = 4 mg/L
Dilution Factor = 300/6
\(BOD = \left( {8 - 4} \right) \times \frac{{300}}{6} = \;200\;mg/L\)Last updated on Jun 2, 2025
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