Question
Download Solution PDFIf \(\rm \frac{k-k\cot^230^\circ}{1+\cot^2 30^{\circ}}\)= sin2 60° + 4 tan245° - cosec260°, then the value of k (correct to two decimal places) is :
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
\(\rm \frac{k-k\cot^230^\circ}{1+\cot^2 30^{\circ}}\)= sin2 60° + 4 tan245° - cosec260°
Concept used:
Calculation:
\(\rm \frac{k-k\cot^230^\circ}{1+\cot^2 30^{\circ}}\)= sin2 60° + 4 tan245° - cosec260°
⇒ \(k \frac {1 - 3}{1 + 3}\) = 3/4 + 4 × 1 - 4/3
⇒ \(\frac {-k}{2}\) = 41/12
⇒ k = -41/6
⇒ k ≈ -6.83
∴ The value of k is -6.83.
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