Question
Download Solution PDFIf x2 + kx + k = 0 has two distinct real solutions, then the value of k will satisfy:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
For two distinct real solutions, D > 0,
Where D = b2 - 4ac
Calculation:
⇒ k2 - 4k > 0
⇒ k(k - 4) > 0
⇒ (k - 0) (k - 4) > 0
Case: I k > 0 & k - 4 & 0
From here, we will get
k > 4
Case: II k < 0 & k < 4
From here, we will get
k < 0
Hence, the solution will be k < 0 or k > 4.
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