Question
Download Solution PDFIf two vectors \(\vec{A}=6\hat{i}-8\hat{j}+4\hat{k}\) and \(\vec{B}=4\hat{i}-6\hat{j}+p\hat{k}\) are mutually perpendicular, then value of p is
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFCONCEPT:
The dot product of vector:
- The dot product is the sum of the products of the corresponding entries of the two sequences of numbers.
- Geometrically, it is the product of the Euclidean magnitudes of the two vectors and the cosine of the angle between them.
\({{\rm{A}}_1}\cdot{{\rm{A}}_2} = \left| {\overrightarrow {{{\rm{A}}_1}} } \right|\left| {\overrightarrow {{{\rm{A}}_2}} } \right|\cos {\rm{θ }}\)
Where \(\left| {\overrightarrow {{{\rm{A}}_1}} } \right|.\left| {\overrightarrow {{{\rm{A}}_2}} } \right|\) are the magnitudes of two vectors A1 and A2
CALCULATION:
Given - \(\vec{A}=6\hat{i}-8\hat{j}+4\hat{k}\) , \(\vec{B}=4\hat{i}-6\hat{j}+p\hat{k}\) and θ - 90°
- Here the two vectors are perpendicular, therefore the scalar product is equal to zero i.e.,
\(⇒ \left| {\overrightarrow {{{\rm{A}}_1}} } \right|\left| {\overrightarrow {{{\rm{A}}_2}} } \right|\cos {\rm{90^\circ =0}}\)
- The dot product of vector is
\(⇒ (6\hat{i}-8\hat{j}+4\hat{k})\cdot(4\hat{i}-6\hat{j}+p\hat{k})=0\)
\(⇒ 24+48+4p = 0\)
⇒ p = -18
Parallel Vectors:
- “Two vectors \(\vec A\) and \(\vec B\) are parallel if and only if they are scalar multiples of one another.”
OR
- If the angle between two vectors is 0° or 180°, then these two vectors are said to be parallel.
Last updated on Jul 17, 2025
-> RPSC 2nd Grade Senior Teacher Exam 2025 Notification has been released on 17th July 2025
-> 6500 vacancies for the post of RPSC Senior Teacher 2nd Grade has been announced.
-> RPSC 2nd Grade Senior Teacher Exam 2025 applications can be submitted online between 19th August and 17th September 2025
-> The Exam dates are yet to be announced.