If two vectors \(\vec{A}=6\hat{i}-8\hat{j}+4\hat{k}\) and \(\vec{B}=4\hat{i}-6\hat{j}+p\hat{k}\) are mutually perpendicular, then value of p is

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Official Sr. Teacher Gr II NON-TSP Science (Held on : 1 Nov 2018)
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  1. -9
  2. -18
  3. +4
  4. 0

Answer (Detailed Solution Below)

Option 2 : -18
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Sr. Teacher Gr II NON-TSP GK Previous Year Official questions Quiz 4
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Detailed Solution

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CONCEPT:

The dot product of vector:

  • The dot product is the sum of the products of the corresponding entries of the two sequences of numbers.
  • Geometrically, it is the product of the Euclidean magnitudes of the two vectors and the cosine of the angle between them.

\({{\rm{A}}_1}\cdot{{\rm{A}}_2} = \left| {\overrightarrow {{{\rm{A}}_1}} } \right|\left| {\overrightarrow {{{\rm{A}}_2}} } \right|\cos {\rm{θ }}\)

Where \(\left| {\overrightarrow {{{\rm{A}}_1}} } \right|.\left| {\overrightarrow {{{\rm{A}}_2}} } \right|\) are the magnitudes of two vectors A1 and A2

CALCULATION:

Given - \(\vec{A}=6\hat{i}-8\hat{j}+4\hat{k}\) ,  \(\vec{B}=4\hat{i}-6\hat{j}+p\hat{k}\) and θ - 90° 

  • Here the two vectors are perpendicular, therefore the scalar product is equal to zero  i.e., 

\(⇒ \left| {\overrightarrow {{{\rm{A}}_1}} } \right|\left| {\overrightarrow {{{\rm{A}}_2}} } \right|\cos {\rm{90^\circ =0}}\)

  • The dot product of vector is 

\(⇒ (6\hat{i}-8\hat{j}+4\hat{k})\cdot(4\hat{i}-6\hat{j}+p\hat{k})=0\)

\(⇒ 24+48+4p = 0\)

⇒ p = -18

26 June 1

Parallel Vectors:

  • “Two vectors \(\vec A\) and \(\vec B\) are parallel if and only if they are scalar multiples of one another.”

OR 

  • If the angle between two vectors is 0° or 180°, then these two vectors are said to be parallel. 
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