Question
Download Solution PDFIf the supply voltage is 160 V, the value of power dissipated in the 10 Ω resistor will be:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept
The power dissipated in a resistor is given by:
\(P={V^2\over R}\)
where, P = Power
V = Voltage
R = Resistance
Calculation
10 Ω and 15 Ω are in parallel.
\(R_{eq}={10× 15 \over 10+15}=6Ω \)
The voltage across Req is:
\(V={6\over 16}\times 160=60V\)
The voltage in parallel remains the same.
The power across 10 Ω resistance is:
\(P={(60)^2\over 10}\)
P = 360 W
Last updated on Jun 16, 2025
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