यदि आपूर्ति वोल्टेज 160 V है, तो 10 Ω प्रतिरोधक में क्षय शक्ति का मान होगा:

F3 Vilas Engineering 8.12.2022 D7

This question was previously asked in
SSC JE Electrical 14 Nov 2022 Shift 3 Official Paper
View all SSC JE EE Papers >
  1. 1000 W
  2. 6 W
  3. 100 W 
  4. 360 W

Answer (Detailed Solution Below)

Option 4 : 360 W
Free
RRB JE CBT I Full Test - 23
14.3 K Users
100 Questions 100 Marks 90 Mins

Detailed Solution

Download Solution PDF

संकल्पना​

प्रतिरोध में क्षय शक्ति निम्न द्वारा दी जाती है:

\(P={V^2\over R}\)

जहां, P = शक्ति

V = वोल्टेज

R = प्रतिरोध

गणना

10 Ω और 15 Ω समांतर क्रम में हैं।

\(R_{eq}={10× 15 \over 10+15}=6Ω \)

F3 Vilas Engineering 8.12.2022 D8

Req के पार्श्व में वोल्टेज है:

\(V={6\over 16}\times 160=60V\)

समानांतर में वोल्टेज समान रहता है।

F3 Vilas Engineering 8.12.2022 D9

10 Ω प्रतिरोध के पार्श्व में शक्ति है:

\(P={(60)^2\over 10}\)

P = 360 W

Latest SSC JE EE Updates

Last updated on Jun 16, 2025

-> SSC JE Electrical 2025 Notification will be released on June 30 for the post of Junior Engineer Electrical/ Electrical & Mechanical.

-> Applicants can fill out the SSC JE application form 2025 for Electrical Engineering from June 30 to July 21.

-> SSC JE EE 2025 paper 1 exam will be conducted from October 27 to 31. 

-> Candidates with a degree/diploma in engineering are eligible for this post.

-> The selection process includes Paper I and Paper II online exams, followed by document verification.

-> Prepare for the exam using SSC JE EE Previous Year Papers.

More Network Elements Questions

Get Free Access Now
Hot Links: teen patti diya teen patti all game teen patti master real cash