If the bulk modulus is K, modulus of Elasticity is E and Poisson’s ratio is $\frac{1}{m}$ , then which of the following is true ?

Question

Question

This question was previously asked in

UKPSC JE Mechanical 2013 Official Paper I

Answer 1

Explanation:

The relation between Young’s modulus (E), rigidity modulus (G) and poison’s ratio (μ) is given by

E = 2G (1 + μ)

Some other important relations are as follows:

E = 3K (1 - 2μ)

$E = \frac{9 K G}{3 K + G}$

Here, Poission ratio (μ) = $\frac{1}{m}$

Therefore, $E = 3 K (1 - 2 μ) = 3 K (1 - \frac{2}{m})$