If currents in two parallel wires flow in opposite directions, the force between the wires will be

  1. attractive
  2. repulsive
  3. zero
  4. attractive or repulsive depending on the material of wires.

Answer (Detailed Solution Below)

Option 2 : repulsive
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NDA 01/2025: English Subject Test
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Detailed Solution

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CONCEPT:

Magnetic field:

  • The space or region around the current-carrying wire/moving electric charge or around the magnetic material in which force of magnetism can be experienced by other magnetic material is called as magnetic field/magnetic induction by that material/current.
  • It is denoted by B.
  • The magnetic force per unit length between two parallel wires is given by;

\(\frac{F}{l} = \frac{{{\mu _o}}}{{2\pi }}\frac{{{I_1}{I_2}}}{d}\)

Where μ0 = permittivity of free space, I1 = current in a first wire, I2 = current in a second wire,d = distance between two wires, and l = length of current-carrying wire.

EXPLANATION:​ 

  • The magnetic force per unit length between two parallel wires is given by;

\(\frac{F}{l} = \frac{{{\mu _o}}}{{2\pi }}\frac{{{I_1}{I_2}}}{d}\)

  • If the conductor carries the current in the same direction, then the force between them will be attractive.
  • If the conductor carries the current in the opposite direction, then the force between them will be repulsive. Therefore option 2 is correct.
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