If a complex number has arg(z) =  and the product of real and imaginary part is 3√3, find the conjugate of the complex number z.

  1. √3 + 3i
  2. √3 - 3i
  3. -√3 - 3i
  4. -√3 + 3i

Answer (Detailed Solution Below)

Option 2 : √3 - 3i
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Detailed Solution

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Concept:

Let z = x + iy be a complex number.

  • Modulus of z = 
  • arg (z) = arg (x + iy) = 
  • Conjugate of z = x - iy


Calculation:

Let z = x + iy

According to the question 

arg(z) = 

⇒  

⇒ y = x

Also given xy = 3

⇒ y = 

Comparing the values of y, we get

⇒ 

⇒ x2 = 3

⇒ x = ± 

∴ x =  {∵ arg(z) lies in first quadrant so -ve value is neglected}

Also y = x = 3

Complex number z = x + iy =  + 3i

Conjugate of z = (z̅) =  - 3i

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