If A = \(\begin{bmatrix} -3 & 4\\ 0 & 1 \end{bmatrix}\) then A - AT is equal to ?

  1. \(\begin{bmatrix} 0 &-4 \\ -4&0 \end{bmatrix}\)
  2. \(\begin{bmatrix} 0 &4 \\ 4&0 \end{bmatrix}\)
  3. \(\begin{bmatrix} 0 &4 \\ -4&0 \end{bmatrix}\)
  4. \(\begin{bmatrix} 0 &-4 \\ 4&0 \end{bmatrix}\)

Answer (Detailed Solution Below)

Option 3 : \(\begin{bmatrix} 0 &4 \\ -4&0 \end{bmatrix}\)
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Detailed Solution

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Concept:

Transpose of a Matrix:

The new matrix obtained by interchanging the rows and columns of the original matrix is called as the transpose of the matrix.

It is denoted by A′ or AT

 

Calculation:

Given:

A = \(\begin{bmatrix} -3 & 4\\ 0 & 1 \end{bmatrix}\)

Now find the transpose of a matrix A,

AT = \(\begin{bmatrix} -3 & 0\\ 4 & 1 \end{bmatrix}\)

Now,

A - AT = \(\begin{bmatrix} -3 & 4\\ 0 & 1 \end{bmatrix}-\begin{bmatrix} -3 & 0\\ 4 & 1 \end{bmatrix}\)

\(= \begin{bmatrix} 0 &4 \\ -4&0 \end{bmatrix}\)

 

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