Question
Download Solution PDFHow many three- digits numbers are there which are divisible by 9 .
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
nth term of A.P are a, a + d , a + 2d, . . . . ,a + (n - 1) d .
Tn = a + (n - 1) d
Where a = first term and d = common difference
Calculation:
Three- digit numbers are divisible by 9 are 108, 117, 126 . . . . 999
Series of AP 108,117, 126 . . . . 999
As we know that, Tn = a + (n - 1) d
⇒ 999 = 108 + (n - 1) 9
⇒ 891 = (n - 1) 9
⇒ 99 = n - 1
⇒ n = 100.
The correct option is 3.
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