m तथा 4m द्रव्यमान की दो वस्तुएं समान गतिज ऊर्जा से गतिमान हैं। वे जिस वेग से गति करती हैं उसका अनुपात क्या होगा?

This question was previously asked in
Bihar STET TGT (Science) Official Paper-I (Held On: 08 Sept, 2023 Shift 1)
View all Bihar STET Papers >
  1. 3 ∶ 4 
  2. 4 ∶ 5
  3. 2 ∶ 1
  4. 1: ∶ 2

Answer (Detailed Solution Below)

Option 3 : 2 ∶ 1
Free
Bihar STET Paper 1 Social Science Full Test 1
150 Qs. 150 Marks 150 Mins

Detailed Solution

Download Solution PDF

गणना:

दिया गया है, m1 = m, m2 = 4m, और साथ ही K.E1 = K.E2

यहाँ, गतिज ऊर्जा = 1/2 (मीटर × वेग2

इस प्रकार, उपरोक्त शर्त के अनुसार
K.E1 = K.E2

1/2 (m × v12) = 1/2 (4m × v22)

v1 = 2 v2, v1 : v2 = 2:1

Latest Bihar STET Updates

Last updated on Jul 3, 2025

-> The Bihar STET 2025 Notification will be released soon.

->  The written exam will consist of  Paper-I and Paper-II  of 150 marks each. 

-> The candidates should go through the Bihar STET selection process to have an idea of the selection procedure in detail.

-> For revision and practice for the exam, solve Bihar STET Previous Year Papers.

More Momentum and Kinetic Energy in Collisions Questions

More Center of Mass and Linear Momentum Questions

Hot Links: lotus teen patti teen patti cash teen patti 500 bonus teen patti master 2023 teen patti circle