30 dB के लाभ के साथ रैखिक ऐम्प्लीफायर को 1.0 μW शक्ति के साथ सिंचित किया जाता है। तो ऐम्प्लीफायर की आउटपुट शक्ति क्या है?

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SDSC ISRO Technical Assistant Electronics 8 April 2018 Official Paper
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  1. 1.0 W
  2. 0 dBm
  3. 30 dBm
  4. -30 dBm

Answer (Detailed Solution Below)

Option 2 : 0 dBm
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संकल्पना:

dB में लाभ को निम्न रूप में परिभाषित किया गया है:

\(P(dB)=10~log_{10}\frac{P_{out}}{P_{in}}\)

dBm में शक्ति को निम्न रूप में व्यक्त किया गया है:

\(P(dBm)=10log_{10}(\frac{P}{1m})\)

P = dBm में व्यक्त की जाने वाली शक्ति

गणना:

दिया गया है

Pin = 1 μW

P(dB) = 30 dB 

उपरोक्त समीकरण में इन मानों को रखने पर, हमें निम्न प्राप्त होता है:

\(30=10~log_{10}\frac{P_{out}}{1~\mu W}\)

\(3=log_{10}\frac{P_{out}}{1~\mu W}\)

दोनों पक्षों पर Antilog लेने पर, हमें निम्न प्राप्त होता है:

\(10^3=\frac{P_{out}}{1~\mu W}\)

Pout = 1 mW

\(P(dBm)=10log_{10}(\frac{1mW}{1mW})\)

P(dBm) = 10log10(1)

P(dBm) = 0 dB

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