Question
Download Solution PDFमाना प्रायिकता द्रव्यमान फलन (x) =
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया है
PMF(x) = 1/2x, x = 1, 2, 3 -----
सूत्र
P(X > 4) = 1 – P(X ≤ 4)
गणना
P(X > 4) = 1 – P(X ≤ 4)
⇒ 1 – [P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)]
⇒ 1 – [1/21 + ½2 + ½3 + ½4]
⇒ 1 – [1/2 + ¼ + 1/8 + 1/16]
⇒ 1 – [(8 + 4 + 2 + 1)/16]
⇒ 1 – [15/16]
⇒ (16 – 15)/16
∴ P(X > 4) का मान 1/16 है।
प्रायिकता द्रव्यमान फलन या PMF को क्रमित युग्म [x, f(x)] के समुच्चय के रूप में परिभाषित किया जाता है यदि प्रत्येक संभावित परिणाम x के लिए f(x) निम्नलिखित शर्त को पूरा करता है
F(x) ≥ 0
∑ f(x) = 1
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