यदि चार पासों को एकसाथ उछाला जाता है, तो वह प्रायिकता क्या है कि उनपर दिखाई देने वाली संख्याओं का योग 25 है?

  1. 0
  2. 1/2
  3. 1
  4. 1/1296

Answer (Detailed Solution Below)

Option 1 : 0
Free
Electric charges and coulomb's law (Basic)
10 Qs. 10 Marks 10 Mins

Detailed Solution

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संकल्पना:

एक घटना के घटित होने की प्रायिकता 

यदि एक पासे को उछाला जाता है, तो प्रतिदर्श समष्‍टियों की संख्या = 6 है, यदि दो पासे को उछाला जाता है, तो n(S) = 62 = 36 है। 

गणना:

यहाँ, चार पासे को उछाला जाता है, 

n(S) = 64

अब, उनपर दिखाई देने वाली संख्या का योग 25 = { }       

⇒ n = 0               

(∵अधिकतम योग = 6 + 6 + 6 + 6 = 24)

∴ प्रायिकता = 0/(64) = 0

अतः विकल्प (1) सही है। 

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