Question
Download Solution PDFनिम्नलिखित आयतचित्र वर्ग अंतरालों के विपरीत निश्चित बारंबारता बंटन को दर्शाता है।
इस बंटन का अनुमानित माध्य है:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसूत्र
माध्य = ∑fx/∑f
गणना
|
अंतराल |
मध्य – बिंदु (x) |
बारंबारता(f) |
Fx |
|
10 – 20 |
15 |
8 |
120 |
|
20 – 30 |
25 |
20 |
500 |
|
30 – 40 |
35 |
16 |
560 |
|
40 – 50 |
45 |
24 |
1080 |
|
50 – 60 |
55 |
12 |
660 |
|
60 – 70 |
65 |
4 |
260 |
|
कुल |
|
84 |
3180 |
⇒ माध्य = 3180/84
∴ माध्य 37.86 (लगभग) है।
Last updated on Jun 13, 2025
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