Question
Download Solution PDFप्रत्यक्ष संपीड़न, संपीडित बंकन और फ्लेक्सुरल तनाव क्षेत्र में क्रमशः M25 कंक्रीट डिजाइन क्षमता
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसंकल्पना:
लिमिट स्टेट विधि,
प्रत्यक्ष संपीड़न में क्षमता = 0.40 × fck
झुकने संपीड़न में क्षमता = 0.45 × fck
लचीले तनाव में क्षमता = 0.7 × √fck
जहां, fck कंक्रीट की अभिलक्षणिक सामर्थ्य है।
गणना:
fck = 25
प्रत्यक्ष संपीड़न में क्षमता = 0.40 × fck = 0.40 × 25 = 10 MPa
झुकने संपीड़न में क्षमता = 0.45 × fck = 0.45 × 25 = 11.25 MPa
लचीले तनाव में क्षमता = 0.7 × √fck=0.7 × 5 = 3.5 MPa
Last updated on Jun 23, 2025
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