Question
Download Solution PDFA और B स्वतंत्र घटनाएँ हैं। A और B के पक्ष में ऑड्स क्रमशः 1:1 और 3:2 हैं। दो घटनाओं में से केवल एक के घटित होने की प्रायिकता ज्ञात कीजिए?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया है
A और B के पक्ष में ऑड्स क्रमशः 1 : 1 और 3 : 2 हैं।
P(A) = 1/2
P(B) = 3/5
गणना
घटनाएँ स्वतंत्र हैं
⇒ P(A ∩ B) = P(A) × P(B)
⇒ 1/2 × 3/5 = 3/10
केवल एक के घटित होने की प्रायिकता
⇒ P(A) – P(A ∩ B) + [P(B) - P(A ∩ B)]
⇒ (1/2 – 3/10) + [3/5 – 3/10]
⇒ 1/2 + 3/5 – 6/10
∴ केवल एक के घटित होने की प्रायिकता 1/2 है।
Last updated on Jun 13, 2025
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