Question
Download Solution PDFFind the value of sin-1 (sin x), x∈ [-π/2, π/2]
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFExplanation:
| Function | Domain | Range of Principal Value |
| sin-1 x | [-1, 1] | [-π/2, π/2] |
| cos-1 x | [-1, 1] | [0, π] |
| csc-1 x | R - (-1, 1) | [-π/2, π/2] - {0} |
| sec-1 x | R - (-1, 1) | [0, π] - {π/2} |
| tan-1 x | R | (-π/2, π/2) |
| cot-1 x | R | (0, π) |
Given: x∈ [-π/2, π/2]
sin-1 (sin x) = x
Last updated on Jun 30, 2025
->Indian Airforce Agniveer (02/2026) Notification has been released. Interested candidates can apply between 11th July to 31st July 2025.
->The Examination will be held 25th September 2025 onwards.
-> Earlier, Indian Airforce Agniveer Group X 2025 Last date had been extended.
-> Candidates applied online from 7th to 2nd February 2025.
-> The online examination was conducted from 22nd March 2025 onwards.
-> The selection of the candidates will depend on three stages which are Phase 1 (Online Written Test), Phase 2 ( DV, Physical Fitness Test, Adaptability Test), and Phase 3 (Medical Examination).
-> The candidates who will qualify all the stages of selection process will be selected for the Air Force Group X posts & will receive a salary ranging of Rs. 30,000.
-> This is one of the most sought jobs. Candidates can also check the Airforce Group X Eligibility here.