Each odd digit in the number "95435478162" is substituted by the previous lower digit and each even digit is substituted by the next higher digit and the digits so obtained are rearranged in descending order from left end, what is the sum of the seventh digit from the right end and the fourth digit from the left end after the rearrangement?

Question

Question

Answer 1

Given number: 95435478162

Operation 2: Digits are rearranged in descending order from the left end.

Given number	9	5	4	3	5	4	7	8	1	6	2
Odd digit → (-1) Even digit → (+1)	(-1)	(-1)	(+1)	(-1)	(-1)	(+1)	(-1)	(+1)	(-1)	(+1)	(+1)
Resultant	8	4	5	2	4	5	6	9	0	7	3
Arranged in descending Order	9	8	7	6	5	5	4	4	3	2	0

So,

Seventh digit from the right end: (Left end) 9 8 7 6 5 5 4 4 3 2 0 (Right end) → 5

Fourth digit from the left end: (Left end) 9 8 7 6 5 5 4 4 3 2 0 (Right end) → 6

So, the required sum = 5 + 6 → 11

Hence, the correct answer is "Option 2".